Faman39
You are making poster board boundary markers in the shape of square pyramids for a relay race. If you are including a 12 -inch square as the bottom and you want the slant height to be 14 inches, how much poster board do you need?
252 in2
420 in2
480 in2
532 in2
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Faman39
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@UnkleRhaukus can you able to help me ?
UnkleRhaukus
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|dw:1352387741795:dw|
Faman39
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I still cant get this, can you able go in bit detail ?
UnkleRhaukus
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can you see how i flattened all the surfaces a plane?
Faman39
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Yes
UnkleRhaukus
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you have a square , and four big triangles,
Faman39
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ok
UnkleRhaukus
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the area of a square is the side length squared
the area of a triangle is half of the base times the height
Faman39
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Are we gonna....multiply 14 and 12?
Faman39
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i am sorry i am totally talking wrong
UnkleRhaukus
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yes the base of the triangles is 12 and they have a height of 14 , the area of each tringle is half these multiplied together
Faman39
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but i got 168 ? :(
UnkleRhaukus
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how?
Faman39
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I do not know, probably i m doing wrong i know :(
Faman39
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that must be for it
UnkleRhaukus
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what did you get for the area of the square?
and what did you get fo the area of each triangle ?
Faman39
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i multiply 14 with 12 :(
UnkleRhaukus
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the area of a triangle is HALF of the base times the height
Faman39
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so half * 14 * 12
UnkleRhaukus
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what do you get?
Faman39
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84 :(
UnkleRhaukus
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right so , one triangle is 84 in^2
what is the area of the square
Faman39
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12?
UnkleRhaukus
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the area of a square is the side length squared
\[12^2=\]
Faman39
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14 ?
Faman39
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sorry about that
UnkleRhaukus
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\[12^2=12\times12=\]
Faman39
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144
UnkleRhaukus
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right
UnkleRhaukus
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the total area is made up of 4 triangles and one square ,
Faman39
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So we divide 4 with 144 ?
UnkleRhaukus
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add the area of the square to four times the area of the triangle
Faman39
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Still not getting any correct point
Faman39
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i am so sorry, i m horrible that i m getting wrong answer
Faman39
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144 * 12 * 4 ?
UnkleRhaukus
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\[A_{\text{square}}=12 [\text{in}]\times12 [\text{in}]=144 [\text{in}]^2\]
\[A_{\text{triangle}}=\frac{14 [\text{in}]\times12 [\text{in}]}2=84 [\text{in}]^2\]
\[SA_{\text{square pyramid}}=A_{\text{square}}\quad+\quad4\times A_{\text{triangle}}\]
Faman39
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Thank you so so much @UnkleRhaukus, your so awesome and genius!!!!!
Faman39
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thanks alot! And i m sorry for troubling :(
Faman39
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i know, i m totally pain, cuz i barely understand thing
UnkleRhaukus
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i hope it makes some sense now,
can you tell me how much poster board do you need?
Faman39
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480 in2
UnkleRhaukus
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\[\color\red\checkmark\]
Faman39
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Thank you so much @UnkleRhaukus !!! your too great!!!!!!