Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
According to Descartes' rule of signs, how many possible negative real roots could the following polynomial function have?
 one year ago
 one year ago
According to Descartes' rule of signs, how many possible negative real roots could the following polynomial function have?
 one year ago
 one year ago

This Question is Closed

iheartfoodBest ResponseYou've already chosen the best response.1
According to Descartes' rule of signs, how many possible negative real roots could the following polynomial function have? A. Four B. Three C. Three or one D. Two or zero **im not too sure but i think the answer is D. two or zero. am i right??
 one year ago

LukeBlueFiveBest ResponseYou've already chosen the best response.1
The number of possible negative real roots is equal or less than the total number of sign changes. How many sign changes do you see?
 one year ago

iheartfoodBest ResponseYou've already chosen the best response.1
2.. i think the answer is D. two or zero... is that correct??
 one year ago

LukeBlueFiveBest ResponseYou've already chosen the best response.1
Yes, I agree with D.
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.