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According to Descartes' rule of signs, how many possible negative real roots could the following polynomial function have?

Mathematics
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According to Descartes' rule of signs, how many possible negative real roots could the following polynomial function have? A. Four B. Three C. Three or one D. Two or zero **im not too sure but i think the answer is D. two or zero. am i right??
The number of possible negative real roots is equal or less than the total number of sign changes. How many sign changes do you see?
2.. i think the answer is D. two or zero... is that correct??

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Other answers:

Yes, I agree with D.
thanks! :)
thanks! :)
You're welcome!

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