anonymous
  • anonymous
According to Descartes' rule of signs, how many possible negative real roots could the following polynomial function have?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
According to Descartes' rule of signs, how many possible negative real roots could the following polynomial function have? A. Four B. Three C. Three or one D. Two or zero **im not too sure but i think the answer is D. two or zero. am i right??
LukeBlueFive
  • LukeBlueFive
The number of possible negative real roots is equal or less than the total number of sign changes. How many sign changes do you see?
anonymous
  • anonymous
2.. i think the answer is D. two or zero... is that correct??

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LukeBlueFive
  • LukeBlueFive
Yes, I agree with D.
anonymous
  • anonymous
thanks! :)
anonymous
  • anonymous
thanks! :)
LukeBlueFive
  • LukeBlueFive
You're welcome!

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