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iheartfood

  • 2 years ago

According to Descartes' rule of signs, how many possible negative real roots could the following polynomial function have?

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  1. iheartfood
    • 2 years ago
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    According to Descartes' rule of signs, how many possible negative real roots could the following polynomial function have? A. Four B. Three C. Three or one D. Two or zero **im not too sure but i think the answer is D. two or zero. am i right??

  2. LukeBlueFive
    • 2 years ago
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    The number of possible negative real roots is equal or less than the total number of sign changes. How many sign changes do you see?

  3. iheartfood
    • 2 years ago
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    2.. i think the answer is D. two or zero... is that correct??

  4. LukeBlueFive
    • 2 years ago
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    Yes, I agree with D.

  5. iheartfood
    • 2 years ago
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    thanks! :)

  6. iheartfood
    • 2 years ago
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    thanks! :)

  7. LukeBlueFive
    • 2 years ago
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    You're welcome!

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