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anonymous
 4 years ago
According to Descartes' rule of signs, how many possible negative real roots could the following polynomial function have?
anonymous
 4 years ago
According to Descartes' rule of signs, how many possible negative real roots could the following polynomial function have?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0According to Descartes' rule of signs, how many possible negative real roots could the following polynomial function have? A. Four B. Three C. Three or one D. Two or zero **im not too sure but i think the answer is D. two or zero. am i right??

LukeBlueFive
 4 years ago
Best ResponseYou've already chosen the best response.1The number of possible negative real roots is equal or less than the total number of sign changes. How many sign changes do you see?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.02.. i think the answer is D. two or zero... is that correct??

LukeBlueFive
 4 years ago
Best ResponseYou've already chosen the best response.1Yes, I agree with D.
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