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iheartfood
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According to Descartes' rule of signs, how many possible negative real roots could the following polynomial function have?
 one year ago
 one year ago
iheartfood Group Title
According to Descartes' rule of signs, how many possible negative real roots could the following polynomial function have?
 one year ago
 one year ago

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iheartfood Group TitleBest ResponseYou've already chosen the best response.1
According to Descartes' rule of signs, how many possible negative real roots could the following polynomial function have? A. Four B. Three C. Three or one D. Two or zero **im not too sure but i think the answer is D. two or zero. am i right??
 one year ago

LukeBlueFive Group TitleBest ResponseYou've already chosen the best response.1
The number of possible negative real roots is equal or less than the total number of sign changes. How many sign changes do you see?
 one year ago

iheartfood Group TitleBest ResponseYou've already chosen the best response.1
2.. i think the answer is D. two or zero... is that correct??
 one year ago

LukeBlueFive Group TitleBest ResponseYou've already chosen the best response.1
Yes, I agree with D.
 one year ago

iheartfood Group TitleBest ResponseYou've already chosen the best response.1
thanks! :)
 one year ago

iheartfood Group TitleBest ResponseYou've already chosen the best response.1
thanks! :)
 one year ago

LukeBlueFive Group TitleBest ResponseYou've already chosen the best response.1
You're welcome!
 one year ago
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