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radh Group Title

Find the area of the triangle with a = 4 feet, b = 8 feet, and c = 11 feet. Round to the nearest tenth.

  • 2 years ago
  • 2 years ago

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  1. Jas9420 Group Title
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    Can you use the Heron's Formula?

    • 2 years ago
  2. radh Group Title
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    This is in relevance to the sides of a right triangle and the answer choices are: 12.3 ft2 9.3 ft2 14.3 ft2 13.3 ft2

    • 2 years ago
  3. Jas9420 Group Title
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    Oh, a right triangle!

    • 2 years ago
  4. radh Group Title
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    I'm not sure what that is.

    • 2 years ago
  5. Jas9420 Group Title
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    Since 11 is the highest, it must be the hypotenuse. Which means that the other two are the base and height of the right triangle. Now, use the Area of a Triangle Formula. It is Area = Base*Height / 2

    • 2 years ago
  6. radh Group Title
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    See, that's where I got 16 (4/2*8), but that doesn't fit with the answer choices.

    • 2 years ago
  7. Jas9420 Group Title
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    Then shouldn't it be 16? Are your options correct? =?

    • 2 years ago
  8. Jas9420 Group Title
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    Yeah, I know. But that's the only explanation since it's a right angled triangle.

    • 2 years ago
  9. radh Group Title
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    Yep. I posted exactly what the question said in the title and the answer choices.

    • 2 years ago
  10. Jas9420 Group Title
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    Oh. But you did get what I was trying to say, right?

    • 2 years ago
  11. radh Group Title
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    Yeah, but. How would this work with Heron's Formula? (Maybe I've interpreted it wrong; this is a Trig course, so I assumed it would concern Right Triangles, but maybe not?)

    • 2 years ago
  12. Jas9420 Group Title
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    We use Heron's formula when we know all the three sides and the triangle isn't a right angled one. It's a very lengthy process, so we refrain from using it with right angled triangles as they can be better solved using the normal Triangle's Area formula.

    • 2 years ago
  13. Jas9420 Group Title
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    http://jwilson.coe.uga.edu/emt725/heron/image12.gif

    • 2 years ago
  14. radh Group Title
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    Oh. If it helps, we were learning about the Law of Sines in this lesson. (That confused me all the more.) Nothing was said about Heron's Formula here or in subsequent lessons, so I think we can avoid that?

    • 2 years ago
  15. Jas9420 Group Title
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    Yeah, Heron's formula isn't required here if you've been learning Trigonometry.

    • 2 years ago
  16. radh Group Title
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    And the Law of Sines relates to angles/sides, but we're only given sides to work with here. Sigh!

    • 2 years ago
  17. Jas9420 Group Title
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    Which angle of Tan is 1/2?

    • 2 years ago
  18. Jas9420 Group Title
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    There isn't one. *Sigh* We can't find the angles! Do you guys use a calculator? And even if we find the angles, what use is it?!

    • 2 years ago
  19. Jas9420 Group Title
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    We don't use Trigonometry for finding the area. It's only used to find the angles or sides of a right triangle.

    • 2 years ago
  20. radh Group Title
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    We can use calculators, but if I knew how to approach the problem I would've used it. :P

    • 2 years ago
  21. radh Group Title
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    Honestly, I'm not sure. Thank you for your effort, though. I'm probably just going to guess and hope it doesn't account for much of my grade.

    • 2 years ago
  22. Jas9420 Group Title
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    Hehe, we couldn't use calculators. T_T And I wish I remembered how Trigonometry. It was way back in the 9th grade I think. But really, are you sure the question isn't faulty?

    • 2 years ago
  23. radh Group Title
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    On my part, I'm sure it isn't faulty. On the teacher's fault, I'm not sure. I'll ask him about it tomorrow.

    • 2 years ago
  24. Jas9420 Group Title
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    Ah, alright. Good luck with that. =D On a personal note, which grade are you in?

    • 2 years ago
  25. radh Group Title
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    10th. Pre-Calculus.

    • 2 years ago
  26. Jas9420 Group Title
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    Ha. Okay. =]

    • 2 years ago
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