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Find the area of the triangle with a = 4 feet, b = 8 feet, and c = 11 feet. Round to the nearest tenth.
 one year ago
 one year ago
Find the area of the triangle with a = 4 feet, b = 8 feet, and c = 11 feet. Round to the nearest tenth.
 one year ago
 one year ago

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Jas9420Best ResponseYou've already chosen the best response.1
Can you use the Heron's Formula?
 one year ago

radhBest ResponseYou've already chosen the best response.0
This is in relevance to the sides of a right triangle and the answer choices are: 12.3 ft2 9.3 ft2 14.3 ft2 13.3 ft2
 one year ago

radhBest ResponseYou've already chosen the best response.0
I'm not sure what that is.
 one year ago

Jas9420Best ResponseYou've already chosen the best response.1
Since 11 is the highest, it must be the hypotenuse. Which means that the other two are the base and height of the right triangle. Now, use the Area of a Triangle Formula. It is Area = Base*Height / 2
 one year ago

radhBest ResponseYou've already chosen the best response.0
See, that's where I got 16 (4/2*8), but that doesn't fit with the answer choices.
 one year ago

Jas9420Best ResponseYou've already chosen the best response.1
Then shouldn't it be 16? Are your options correct? =?
 one year ago

Jas9420Best ResponseYou've already chosen the best response.1
Yeah, I know. But that's the only explanation since it's a right angled triangle.
 one year ago

radhBest ResponseYou've already chosen the best response.0
Yep. I posted exactly what the question said in the title and the answer choices.
 one year ago

Jas9420Best ResponseYou've already chosen the best response.1
Oh. But you did get what I was trying to say, right?
 one year ago

radhBest ResponseYou've already chosen the best response.0
Yeah, but. How would this work with Heron's Formula? (Maybe I've interpreted it wrong; this is a Trig course, so I assumed it would concern Right Triangles, but maybe not?)
 one year ago

Jas9420Best ResponseYou've already chosen the best response.1
We use Heron's formula when we know all the three sides and the triangle isn't a right angled one. It's a very lengthy process, so we refrain from using it with right angled triangles as they can be better solved using the normal Triangle's Area formula.
 one year ago

Jas9420Best ResponseYou've already chosen the best response.1
http://jwilson.coe.uga.edu/emt725/heron/image12.gif
 one year ago

radhBest ResponseYou've already chosen the best response.0
Oh. If it helps, we were learning about the Law of Sines in this lesson. (That confused me all the more.) Nothing was said about Heron's Formula here or in subsequent lessons, so I think we can avoid that?
 one year ago

Jas9420Best ResponseYou've already chosen the best response.1
Yeah, Heron's formula isn't required here if you've been learning Trigonometry.
 one year ago

radhBest ResponseYou've already chosen the best response.0
And the Law of Sines relates to angles/sides, but we're only given sides to work with here. Sigh!
 one year ago

Jas9420Best ResponseYou've already chosen the best response.1
Which angle of Tan is 1/2?
 one year ago

Jas9420Best ResponseYou've already chosen the best response.1
There isn't one. *Sigh* We can't find the angles! Do you guys use a calculator? And even if we find the angles, what use is it?!
 one year ago

Jas9420Best ResponseYou've already chosen the best response.1
We don't use Trigonometry for finding the area. It's only used to find the angles or sides of a right triangle.
 one year ago

radhBest ResponseYou've already chosen the best response.0
We can use calculators, but if I knew how to approach the problem I would've used it. :P
 one year ago

radhBest ResponseYou've already chosen the best response.0
Honestly, I'm not sure. Thank you for your effort, though. I'm probably just going to guess and hope it doesn't account for much of my grade.
 one year ago

Jas9420Best ResponseYou've already chosen the best response.1
Hehe, we couldn't use calculators. T_T And I wish I remembered how Trigonometry. It was way back in the 9th grade I think. But really, are you sure the question isn't faulty?
 one year ago

radhBest ResponseYou've already chosen the best response.0
On my part, I'm sure it isn't faulty. On the teacher's fault, I'm not sure. I'll ask him about it tomorrow.
 one year ago

Jas9420Best ResponseYou've already chosen the best response.1
Ah, alright. Good luck with that. =D On a personal note, which grade are you in?
 one year ago
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