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coolaidd

  • 3 years ago

Find g(f(x)) for f(x) = -3x – 6 and G(x)=(-1/2)x+3

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  1. v4xN0s
    • 3 years ago
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    Simplify this (-1/2)(-3x-6)+3

  2. radh
    • 3 years ago
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    Multiply (-3x-6) and (-1/2x+3).

  3. Kira_Yamato
    • 3 years ago
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    Is \[G(x) = \int\limits g(x) dx\]

  4. v4xN0s
    • 3 years ago
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    radh thats not right and there is no need for integrals here...

  5. v4xN0s
    • 3 years ago
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    its just simple substitution

  6. radh
    • 3 years ago
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    How is it not right? you multiply g(x) * f(x)..?

  7. coolaidd
    • 3 years ago
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    3/2x+6 ?

  8. v4xN0s
    • 3 years ago
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    you dont multiply you substitue f(x) into g(x)

  9. coolaidd
    • 3 years ago
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    im saying is this the answer?

  10. radh
    • 3 years ago
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    Ah, I understand. Sorry.

  11. v4xN0s
    • 3 years ago
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    no the answer is 3/2x-15

  12. coolaidd
    • 3 years ago
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    oh ok.. thanks!

  13. coolaidd
    • 3 years ago
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    What about : Find f(g(x)) for f(x) = -3x – 6 and g(x)=-1/2x+3

  14. coolaidd
    • 3 years ago
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    3/2x+6?

  15. v4xN0s
    • 3 years ago
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    Oh wow im so sorry i switched then up

  16. v4xN0s
    • 3 years ago
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    3/2x+6 is the right answer to the first one and 3/2x-15 is the answer to the second one

  17. coolaidd
    • 3 years ago
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    i see!

  18. Kira_Yamato
    • 3 years ago
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    I suppose the thing is for all Real values of x. gf(x) = (-1/2)(-3x – 6)+3 gf(x) = 3/2 x + 6

  19. coolaidd
    • 3 years ago
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    thanksss

  20. Kira_Yamato
    • 3 years ago
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    Sorry if I confuse you because I thought G'(x) = g(x) --> saw that in a textbook when I visit Singapore

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