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coolaidd Group Title

Find g(f(x)) for f(x) = -3x – 6 and G(x)=(-1/2)x+3

  • 2 years ago
  • 2 years ago

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  1. v4xN0s Group Title
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    Simplify this (-1/2)(-3x-6)+3

    • 2 years ago
  2. radh Group Title
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    Multiply (-3x-6) and (-1/2x+3).

    • 2 years ago
  3. Kira_Yamato Group Title
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    Is \[G(x) = \int\limits g(x) dx\]

    • 2 years ago
  4. v4xN0s Group Title
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    radh thats not right and there is no need for integrals here...

    • 2 years ago
  5. v4xN0s Group Title
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    its just simple substitution

    • 2 years ago
  6. radh Group Title
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    How is it not right? you multiply g(x) * f(x)..?

    • 2 years ago
  7. coolaidd Group Title
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    3/2x+6 ?

    • 2 years ago
  8. v4xN0s Group Title
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    you dont multiply you substitue f(x) into g(x)

    • 2 years ago
  9. coolaidd Group Title
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    im saying is this the answer?

    • 2 years ago
  10. radh Group Title
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    Ah, I understand. Sorry.

    • 2 years ago
  11. v4xN0s Group Title
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    no the answer is 3/2x-15

    • 2 years ago
  12. coolaidd Group Title
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    oh ok.. thanks!

    • 2 years ago
  13. coolaidd Group Title
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    What about : Find f(g(x)) for f(x) = -3x – 6 and g(x)=-1/2x+3

    • 2 years ago
  14. coolaidd Group Title
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    3/2x+6?

    • 2 years ago
  15. v4xN0s Group Title
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    Oh wow im so sorry i switched then up

    • 2 years ago
  16. v4xN0s Group Title
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    3/2x+6 is the right answer to the first one and 3/2x-15 is the answer to the second one

    • 2 years ago
  17. coolaidd Group Title
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    i see!

    • 2 years ago
  18. Kira_Yamato Group Title
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    I suppose the thing is for all Real values of x. gf(x) = (-1/2)(-3x – 6)+3 gf(x) = 3/2 x + 6

    • 2 years ago
  19. coolaidd Group Title
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    thanksss

    • 2 years ago
  20. Kira_Yamato Group Title
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    Sorry if I confuse you because I thought G'(x) = g(x) --> saw that in a textbook when I visit Singapore

    • 2 years ago
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