anonymous
  • anonymous
Find g(f(x)) for f(x) = -3x – 6 and G(x)=(-1/2)x+3
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
Simplify this (-1/2)(-3x-6)+3
anonymous
  • anonymous
Multiply (-3x-6) and (-1/2x+3).
Kira_Yamato
  • Kira_Yamato
Is \[G(x) = \int\limits g(x) dx\]

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anonymous
  • anonymous
radh thats not right and there is no need for integrals here...
anonymous
  • anonymous
its just simple substitution
anonymous
  • anonymous
How is it not right? you multiply g(x) * f(x)..?
anonymous
  • anonymous
3/2x+6 ?
anonymous
  • anonymous
you dont multiply you substitue f(x) into g(x)
anonymous
  • anonymous
im saying is this the answer?
anonymous
  • anonymous
Ah, I understand. Sorry.
anonymous
  • anonymous
no the answer is 3/2x-15
anonymous
  • anonymous
oh ok.. thanks!
anonymous
  • anonymous
What about : Find f(g(x)) for f(x) = -3x – 6 and g(x)=-1/2x+3
anonymous
  • anonymous
3/2x+6?
anonymous
  • anonymous
Oh wow im so sorry i switched then up
anonymous
  • anonymous
3/2x+6 is the right answer to the first one and 3/2x-15 is the answer to the second one
anonymous
  • anonymous
i see!
Kira_Yamato
  • Kira_Yamato
I suppose the thing is for all Real values of x. gf(x) = (-1/2)(-3x – 6)+3 gf(x) = 3/2 x + 6
anonymous
  • anonymous
thanksss
Kira_Yamato
  • Kira_Yamato
Sorry if I confuse you because I thought G'(x) = g(x) --> saw that in a textbook when I visit Singapore

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