coolaidd
Find g(f(x)) for f(x) = 3x – 6 and G(x)=(1/2)x+3



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v4xN0s
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Simplify this (1/2)(3x6)+3

radh
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Multiply (3x6) and (1/2x+3).

Kira_Yamato
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Is \[G(x) = \int\limits g(x) dx\]

v4xN0s
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radh thats not right and there is no need for integrals here...

v4xN0s
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its just simple substitution

radh
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How is it not right? you multiply g(x) * f(x)..?

coolaidd
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3/2x+6 ?

v4xN0s
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you dont multiply you substitue f(x) into g(x)

coolaidd
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im saying is this the answer?

radh
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Ah, I understand. Sorry.

v4xN0s
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no the answer is 3/2x15

coolaidd
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oh ok.. thanks!

coolaidd
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What about :
Find f(g(x)) for f(x) = 3x – 6 and g(x)=1/2x+3

coolaidd
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3/2x+6?

v4xN0s
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Oh wow im so sorry i switched then up

v4xN0s
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3/2x+6 is the right answer to the first one and 3/2x15 is the answer to the second one

coolaidd
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i see!

Kira_Yamato
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I suppose the thing is for all Real values of x.
gf(x) = (1/2)(3x – 6)+3
gf(x) = 3/2 x + 6

coolaidd
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thanksss

Kira_Yamato
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Sorry if I confuse you because I thought G'(x) = g(x) > saw that in a textbook when I visit Singapore