Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

Callisto Group TitleBest ResponseYou've already chosen the best response.1
Ammonia gas is produced by reacting hydrogen gas with nitrogen gas. To produce 562 g of ammonia gas using air as your source of nitrogen gas, what volume of air is required if the air is introduced at 29°C and 745 mmHg? (the mole fraction of nitrogen gas in air is 0.781)
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.1
1. Write the chemical equation \[N_2 + 3H_2 \rightarrow 2NH_3\]2. Find the number of mole of ammonia gas produced. Can you do it?
 one year ago

johnsonshelby Group TitleBest ResponseYou've already chosen the best response.0
It's so late, I think I did it right...
 one year ago

johnsonshelby Group TitleBest ResponseYou've already chosen the best response.0
32.99864952 mol NH3
 one year ago

johnsonshelby Group TitleBest ResponseYou've already chosen the best response.0
I have to go back to my dorm, I'll be back on in 15 minutes :)
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.1
No. of mole of NH3 = mass/ molar mass = 562 / (14.0067 +1.00794x3) = 32.9996 mol No. of mole of N2 required = no. of mole of NH3 / 2 = ... pV = nRT V = 99.32518055000001kPa = 99.32518055000001 x 10^3 Pa T = 29 degree Celsius = (29+273) K Solve V.
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.1
n = no. of mole of N2 / 0.781
 one year ago

v_shoto Group TitleBest ResponseYou've already chosen the best response.0
after you found the moles of NH3 i couldn't follow your work, is there any way that you could please clarify :D i would greatly appreciate it.
 10 months ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.