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cecekyler
 3 years ago
Sally applies a total force of 299 N with a
rope to drag a wooden crate of mass 100 kg
across a ﬂoor with a constant acceleration in
the xdirection of a = 0.1 m/s
2
. The rope tied
to the crate is pulled at an angle of θ = 59
◦
relative to the ﬂoor.
m
Calculate the total work done by friction as
the block moves a distance 21.8 m over the
horizontal surface. The acceleration due to
gravity is 9.8 m/s
2
.
Answer in units of J
cecekyler
 3 years ago
Sally applies a total force of 299 N with a rope to drag a wooden crate of mass 100 kg across a ﬂoor with a constant acceleration in the xdirection of a = 0.1 m/s 2 . The rope tied to the crate is pulled at an angle of θ = 59 ◦ relative to the ﬂoor. m Calculate the total work done by friction as the block moves a distance 21.8 m over the horizontal surface. The acceleration due to gravity is 9.8 m/s 2 . Answer in units of J

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furnessj
 3 years ago
Best ResponseYou've already chosen the best response.1Do you need help to do it or want an answer? 3140J is what I get..

cecekyler
 3 years ago
Best ResponseYou've already chosen the best response.0i would like how you got the answer too, apparently its really simple but i guess im just missing it

furnessj
 3 years ago
Best ResponseYou've already chosen the best response.1I have to go for lunch, back in 30mins or so if nobody else helps before then. is the answer right..?!

furnessj
 3 years ago
Best ResponseYou've already chosen the best response.1So, first thing is a free body diagram: dw:1352382563028:dw

furnessj
 3 years ago
Best ResponseYou've already chosen the best response.1Then given the acceleration, we work out the resultant force causing that acceleration: F = ma = 100 x 0.1 = 10N Now, we find the force of friction acting against the motion: 10N = Fcos59  F_friction, giving F_friction = 143.99N Now, the work done by this force is: Work = F_friction x distance = 143.99 x 21.8 = 3140J
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