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Sally applies a total force of 299 N with a
rope to drag a wooden crate of mass 100 kg
across a ﬂoor with a constant acceleration in
the xdirection of a = 0.1 m/s
2
. The rope tied
to the crate is pulled at an angle of θ = 59
◦
relative to the ﬂoor.
m
Calculate the total work done by friction as
the block moves a distance 21.8 m over the
horizontal surface. The acceleration due to
gravity is 9.8 m/s
2
.
Answer in units of J
 one year ago
 one year ago
Sally applies a total force of 299 N with a rope to drag a wooden crate of mass 100 kg across a ﬂoor with a constant acceleration in the xdirection of a = 0.1 m/s 2 . The rope tied to the crate is pulled at an angle of θ = 59 ◦ relative to the ﬂoor. m Calculate the total work done by friction as the block moves a distance 21.8 m over the horizontal surface. The acceleration due to gravity is 9.8 m/s 2 . Answer in units of J
 one year ago
 one year ago

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furnessjBest ResponseYou've already chosen the best response.1
Do you need help to do it or want an answer? 3140J is what I get..
 one year ago

cecekylerBest ResponseYou've already chosen the best response.0
i would like how you got the answer too, apparently its really simple but i guess im just missing it
 one year ago

furnessjBest ResponseYou've already chosen the best response.1
I have to go for lunch, back in 30mins or so if nobody else helps before then. is the answer right..?!
 one year ago

furnessjBest ResponseYou've already chosen the best response.1
So, first thing is a free body diagram: dw:1352382563028:dw
 one year ago

furnessjBest ResponseYou've already chosen the best response.1
Then given the acceleration, we work out the resultant force causing that acceleration: F = ma = 100 x 0.1 = 10N Now, we find the force of friction acting against the motion: 10N = Fcos59  F_friction, giving F_friction = 143.99N Now, the work done by this force is: Work = F_friction x distance = 143.99 x 21.8 = 3140J
 one year ago
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