## alyssababy7 2 years ago x varies inversely as y^2, and x = 4 when y = 10. Find x when y = 2. A. x = 16 B. x = 5 C. x = 80 D. x = 100

1. ChmE

$x=\frac{ k }{ y^2 }\rightarrow 4=\frac{ k }{ 10^2 }\rightarrow k=400$$x=\frac{ 400 }{ y^2 }\rightarrow x=\frac{ 400 }{ 2^2 }\rightarrow x=100$

2. ChmE

k is a proportionality constant