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anonymous
 4 years ago
1+2+4+8+16+32.............. = ? Find the Sum
anonymous
 4 years ago
1+2+4+8+16+32.............. = ? Find the Sum

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.01 (1+2+4+8+16+32.............. ) (21)(1+2+4+8+16+32.............. ) = 2 + 4 +8+ 16 +32 ....... 12481632.......... = 1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Lol...i knw....Nw tell me wats the wrong in my sloution

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0huh they haven't given the last term and btw its basically a geometric progression

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Do u Find any mistake in the way i did....

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah !!!!! there is a mistake in ur where did that 1 come from????

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.021 = 1...................lol

mayankdevnani
 4 years ago
Best ResponseYou've already chosen the best response.0... 4, 8, 16, 32 ... 512 or 4(1), 4(2), 4(4), 4(8), ... , 4(128) or 4(2^0), 4(2^1), 4(2^2), 4(2^3), ... , 4(2^7) S(n) = 4 ∑ 2^k [ k = 0 to n ] ....... = 4 [ 2^(n+1)  1 ] S(7) = 4 [ 2^(7+1)  1 ] ....... = 1020

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Lol....i dont need the answer..) i want to knw is there any mistake in my solution

mayankdevnani
 4 years ago
Best ResponseYou've already chosen the best response.0don't angry @Yahoo! it's my limit

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0lol....i am not angry ...this is a Funny....question....

mayankdevnani
 4 years ago
Best ResponseYou've already chosen the best response.0just apply my method and get the answer

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@Yahoo! : its not that let the series be A by ur terms => (21)A =>2A A =A

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oho...Again..... Tell me is there any wrong...lol

mayankdevnani
 4 years ago
Best ResponseYou've already chosen the best response.0\[\Huge{\bf{\color{blue}{i know you can }\color{red}{doit}}}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I hate these! I can't see see what is wrong but obviously there is something as it should total infinity... I would just do the 21 in the bracket and get the same answer... (is it not that there will always be one last term in the positive set of numbers which is much bigger than its negative counterpart in that set, and eventually that is infinity..?)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.01 (1+2+4+8+16+32.............. ) (21)(1+2+4+8+16+32.............. ) = 2 + 4 +8+ 16 +32 ....... 12481632.......... = 1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Also... first terms, 21 = 1, second terms: 42 = 2, so you DO get the original series back, and it does NOT equal 1.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.02+4+8+16+32..................+2n 1+2+4+8+16+32............. + n {subtracting}  1+2+4+8+16 +32+...........n

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0take make sense @DHASHNI

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0exactly @DHASHNI ! have a medal too :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You are subtracting sets of different cardinality. That's like adding unlike terms, you can't do it.

UnkleRhaukus
 4 years ago
Best ResponseYou've already chosen the best response.01 (1+2+4+8+16+32.............. ) (21)(1+2+4+8+16+32.............. ) = (2 + 4 +8+ 16 +32 +64+......)+( 124816 32 .........) = 63+.....
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