## anonymous 4 years ago 1+2+4+8+16+32.............. = ? Find the Sum

1. anonymous

64, 128,256,512

2. anonymous

1 (1+2+4+8+16+32.............. ) (2-1)(1+2+4+8+16+32.............. ) = 2 + 4 +8+ 16 +32 ....... -1-2-4-8-16-32.......... = -1

3. anonymous

its infinity

4. anonymous

Lol...i knw....Nw tell me wats the wrong in my sloution

5. anonymous

huh they haven't given the last term and btw its basically a geometric progression

6. anonymous

Do u Find any mistake in the way i did....

7. anonymous

yeah !!!!! there is a mistake in ur where did that -1 come from????

8. anonymous

2-1 = 1...................lol

9. mayankdevnani

limit help....

10. mayankdevnani

... 4, 8, 16, 32 ... 512 or 4(1), 4(2), 4(4), 4(8), ... , 4(128) or 4(2^0), 4(2^1), 4(2^2), 4(2^3), ... , 4(2^7) S(n) = 4 ∑ 2^k [ k = 0 to n ] ....... = 4 [ 2^(n+1) - 1 ] S(7) = 4 [ 2^(7+1) - 1 ] ....... = 1020

11. anonymous

Lol....i dont need the answer..) i want to knw is there any mistake in my solution

12. mayankdevnani

don't angry @Yahoo! it's my limit

13. anonymous

lol....i am not angry ...this is a Funny....question....

14. mayankdevnani

just apply my method and get the answer

15. anonymous

@Yahoo! : its not that let the series be A by ur terms => (2-1)A =>2A -A =A

16. anonymous

oho...Again..... Tell me is there any wrong...lol

17. anonymous

got it!!!!

18. mayankdevnani

$\Huge{\bf{\color{blue}{i know you can }\color{red}{doit}}}$

19. anonymous

I hate these! I can't see see what is wrong but obviously there is something as it should total infinity... I would just do the 2-1 in the bracket and get the same answer... (is it not that there will always be one last term in the positive set of numbers which is much bigger than its negative counterpart in that set, and eventually that is infinity..?)

20. anonymous

1 (1+2+4+8+16+32.............. ) (2-1)(1+2+4+8+16+32.............. ) = 2 + 4 +8+ 16 +32 ....... -1-2-4-8-16-32.......... = -1

21. anonymous

Also... first terms, 2-1 = 1, second terms: 4-2 = 2, so you DO get the original series back, and it does NOT equal -1.

22. anonymous

2+4+8+16+32..................+2n 1+2+4+8+16+32............. + n {subtracting} ----------------------------- 1+2+4+8+16 +32+...........n

23. anonymous

take make sense @DHASHNI

24. anonymous

WAT!!!

25. anonymous

*that

26. anonymous

Sorry

27. anonymous

exactly @DHASHNI ! have a medal too :)

28. anonymous

You are subtracting sets of different cardinality. That's like adding unlike terms, you can't do it.

29. UnkleRhaukus

1 (1+2+4+8+16+32.............. ) (2-1)(1+2+4+8+16+32.............. ) = (2 + 4 +8+ 16 +32 +64+......)+( -1-2-4-8-16 -32 .........) = 63+.....