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Yahoo!

  • 2 years ago

1+2+4+8+16+32.............. = ? Find the Sum

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  1. DhopeChickita
    • 2 years ago
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    64, 128,256,512

  2. Yahoo!
    • 2 years ago
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    1 (1+2+4+8+16+32.............. ) (2-1)(1+2+4+8+16+32.............. ) = 2 + 4 +8+ 16 +32 ....... -1-2-4-8-16-32.......... = -1

  3. DHASHNI
    • 2 years ago
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    its infinity

  4. Yahoo!
    • 2 years ago
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    Lol...i knw....Nw tell me wats the wrong in my sloution

  5. DHASHNI
    • 2 years ago
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    huh they haven't given the last term and btw its basically a geometric progression

  6. Yahoo!
    • 2 years ago
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    Do u Find any mistake in the way i did....

  7. DHASHNI
    • 2 years ago
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    yeah !!!!! there is a mistake in ur where did that -1 come from????

  8. Yahoo!
    • 2 years ago
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    2-1 = 1...................lol

  9. mayankdevnani
    • 2 years ago
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    limit help....

  10. mayankdevnani
    • 2 years ago
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    ... 4, 8, 16, 32 ... 512 or 4(1), 4(2), 4(4), 4(8), ... , 4(128) or 4(2^0), 4(2^1), 4(2^2), 4(2^3), ... , 4(2^7) S(n) = 4 ∑ 2^k [ k = 0 to n ] ....... = 4 [ 2^(n+1) - 1 ] S(7) = 4 [ 2^(7+1) - 1 ] ....... = 1020

  11. Yahoo!
    • 2 years ago
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    Lol....i dont need the answer..) i want to knw is there any mistake in my solution

  12. mayankdevnani
    • 2 years ago
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    don't angry @Yahoo! it's my limit

  13. Yahoo!
    • 2 years ago
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    lol....i am not angry ...this is a Funny....question....

  14. mayankdevnani
    • 2 years ago
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    just apply my method and get the answer

  15. DHASHNI
    • 2 years ago
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    @Yahoo! : its not that let the series be A by ur terms => (2-1)A =>2A -A =A

  16. Yahoo!
    • 2 years ago
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    oho...Again..... Tell me is there any wrong...lol

  17. DHASHNI
    • 2 years ago
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    got it!!!!

  18. mayankdevnani
    • 2 years ago
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    \[\Huge{\bf{\color{blue}{i know you can }\color{red}{doit}}}\]

  19. furnessj
    • 2 years ago
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    I hate these! I can't see see what is wrong but obviously there is something as it should total infinity... I would just do the 2-1 in the bracket and get the same answer... (is it not that there will always be one last term in the positive set of numbers which is much bigger than its negative counterpart in that set, and eventually that is infinity..?)

  20. Yahoo!
    • 2 years ago
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    1 (1+2+4+8+16+32.............. ) (2-1)(1+2+4+8+16+32.............. ) = 2 + 4 +8+ 16 +32 ....... -1-2-4-8-16-32.......... = -1

  21. furnessj
    • 2 years ago
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    Also... first terms, 2-1 = 1, second terms: 4-2 = 2, so you DO get the original series back, and it does NOT equal -1.

  22. DHASHNI
    • 2 years ago
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    2+4+8+16+32..................+2n 1+2+4+8+16+32............. + n {subtracting} ----------------------------- 1+2+4+8+16 +32+...........n

  23. Yahoo!
    • 2 years ago
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    take make sense @DHASHNI

  24. DHASHNI
    • 2 years ago
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    WAT!!!

  25. Yahoo!
    • 2 years ago
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    *that

  26. Yahoo!
    • 2 years ago
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    Sorry

  27. furnessj
    • 2 years ago
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    exactly @DHASHNI ! have a medal too :)

  28. CliffSedge
    • 2 years ago
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    You are subtracting sets of different cardinality. That's like adding unlike terms, you can't do it.

  29. UnkleRhaukus
    • 2 years ago
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    1 (1+2+4+8+16+32.............. ) (2-1)(1+2+4+8+16+32.............. ) = (2 + 4 +8+ 16 +32 +64+......)+( -1-2-4-8-16 -32 .........) = 63+.....

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