anonymous
  • anonymous
1+2+4+8+16+32.............. = ? Find the Sum
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
64, 128,256,512
anonymous
  • anonymous
1 (1+2+4+8+16+32.............. ) (2-1)(1+2+4+8+16+32.............. ) = 2 + 4 +8+ 16 +32 ....... -1-2-4-8-16-32.......... = -1
anonymous
  • anonymous
its infinity

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anonymous
  • anonymous
Lol...i knw....Nw tell me wats the wrong in my sloution
anonymous
  • anonymous
huh they haven't given the last term and btw its basically a geometric progression
anonymous
  • anonymous
Do u Find any mistake in the way i did....
anonymous
  • anonymous
yeah !!!!! there is a mistake in ur where did that -1 come from????
anonymous
  • anonymous
2-1 = 1...................lol
mayankdevnani
  • mayankdevnani
limit help....
mayankdevnani
  • mayankdevnani
... 4, 8, 16, 32 ... 512 or 4(1), 4(2), 4(4), 4(8), ... , 4(128) or 4(2^0), 4(2^1), 4(2^2), 4(2^3), ... , 4(2^7) S(n) = 4 ∑ 2^k [ k = 0 to n ] ....... = 4 [ 2^(n+1) - 1 ] S(7) = 4 [ 2^(7+1) - 1 ] ....... = 1020
anonymous
  • anonymous
Lol....i dont need the answer..) i want to knw is there any mistake in my solution
mayankdevnani
  • mayankdevnani
don't angry @Yahoo! it's my limit
anonymous
  • anonymous
lol....i am not angry ...this is a Funny....question....
mayankdevnani
  • mayankdevnani
just apply my method and get the answer
anonymous
  • anonymous
@Yahoo! : its not that let the series be A by ur terms => (2-1)A =>2A -A =A
anonymous
  • anonymous
oho...Again..... Tell me is there any wrong...lol
anonymous
  • anonymous
got it!!!!
mayankdevnani
  • mayankdevnani
\[\Huge{\bf{\color{blue}{i know you can }\color{red}{doit}}}\]
anonymous
  • anonymous
I hate these! I can't see see what is wrong but obviously there is something as it should total infinity... I would just do the 2-1 in the bracket and get the same answer... (is it not that there will always be one last term in the positive set of numbers which is much bigger than its negative counterpart in that set, and eventually that is infinity..?)
anonymous
  • anonymous
1 (1+2+4+8+16+32.............. ) (2-1)(1+2+4+8+16+32.............. ) = 2 + 4 +8+ 16 +32 ....... -1-2-4-8-16-32.......... = -1
anonymous
  • anonymous
Also... first terms, 2-1 = 1, second terms: 4-2 = 2, so you DO get the original series back, and it does NOT equal -1.
anonymous
  • anonymous
2+4+8+16+32..................+2n 1+2+4+8+16+32............. + n {subtracting} ----------------------------- 1+2+4+8+16 +32+...........n
anonymous
  • anonymous
take make sense @DHASHNI
anonymous
  • anonymous
WAT!!!
anonymous
  • anonymous
*that
anonymous
  • anonymous
Sorry
anonymous
  • anonymous
exactly @DHASHNI ! have a medal too :)
anonymous
  • anonymous
You are subtracting sets of different cardinality. That's like adding unlike terms, you can't do it.
UnkleRhaukus
  • UnkleRhaukus
1 (1+2+4+8+16+32.............. ) (2-1)(1+2+4+8+16+32.............. ) = (2 + 4 +8+ 16 +32 +64+......)+( -1-2-4-8-16 -32 .........) = 63+.....

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