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Yahoo!

1+2+4+8+16+32.............. = ? Find the Sum

  • one year ago
  • one year ago

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  1. DhopeChickita
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    64, 128,256,512

    • one year ago
  2. Yahoo!
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    1 (1+2+4+8+16+32.............. ) (2-1)(1+2+4+8+16+32.............. ) = 2 + 4 +8+ 16 +32 ....... -1-2-4-8-16-32.......... = -1

    • one year ago
  3. DHASHNI
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    its infinity

    • one year ago
  4. Yahoo!
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    Lol...i knw....Nw tell me wats the wrong in my sloution

    • one year ago
  5. DHASHNI
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    huh they haven't given the last term and btw its basically a geometric progression

    • one year ago
  6. Yahoo!
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    Do u Find any mistake in the way i did....

    • one year ago
  7. DHASHNI
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    yeah !!!!! there is a mistake in ur where did that -1 come from????

    • one year ago
  8. Yahoo!
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    2-1 = 1...................lol

    • one year ago
  9. mayankdevnani
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    limit help....

    • one year ago
  10. mayankdevnani
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    ... 4, 8, 16, 32 ... 512 or 4(1), 4(2), 4(4), 4(8), ... , 4(128) or 4(2^0), 4(2^1), 4(2^2), 4(2^3), ... , 4(2^7) S(n) = 4 ∑ 2^k [ k = 0 to n ] ....... = 4 [ 2^(n+1) - 1 ] S(7) = 4 [ 2^(7+1) - 1 ] ....... = 1020

    • one year ago
  11. Yahoo!
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    Lol....i dont need the answer..) i want to knw is there any mistake in my solution

    • one year ago
  12. mayankdevnani
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    don't angry @Yahoo! it's my limit

    • one year ago
  13. Yahoo!
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    lol....i am not angry ...this is a Funny....question....

    • one year ago
  14. mayankdevnani
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    just apply my method and get the answer

    • one year ago
  15. DHASHNI
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    @Yahoo! : its not that let the series be A by ur terms => (2-1)A =>2A -A =A

    • one year ago
  16. Yahoo!
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    oho...Again..... Tell me is there any wrong...lol

    • one year ago
  17. DHASHNI
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    got it!!!!

    • one year ago
  18. mayankdevnani
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    \[\Huge{\bf{\color{blue}{i know you can }\color{red}{doit}}}\]

    • one year ago
  19. furnessj
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    I hate these! I can't see see what is wrong but obviously there is something as it should total infinity... I would just do the 2-1 in the bracket and get the same answer... (is it not that there will always be one last term in the positive set of numbers which is much bigger than its negative counterpart in that set, and eventually that is infinity..?)

    • one year ago
  20. Yahoo!
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    1 (1+2+4+8+16+32.............. ) (2-1)(1+2+4+8+16+32.............. ) = 2 + 4 +8+ 16 +32 ....... -1-2-4-8-16-32.......... = -1

    • one year ago
  21. furnessj
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    Also... first terms, 2-1 = 1, second terms: 4-2 = 2, so you DO get the original series back, and it does NOT equal -1.

    • one year ago
  22. DHASHNI
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    2+4+8+16+32..................+2n 1+2+4+8+16+32............. + n {subtracting} ----------------------------- 1+2+4+8+16 +32+...........n

    • one year ago
  23. Yahoo!
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    take make sense @DHASHNI

    • one year ago
  24. DHASHNI
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    WAT!!!

    • one year ago
  25. Yahoo!
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    *that

    • one year ago
  26. Yahoo!
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    Sorry

    • one year ago
  27. furnessj
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    exactly @DHASHNI ! have a medal too :)

    • one year ago
  28. CliffSedge
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    You are subtracting sets of different cardinality. That's like adding unlike terms, you can't do it.

    • one year ago
  29. UnkleRhaukus
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    1 (1+2+4+8+16+32.............. ) (2-1)(1+2+4+8+16+32.............. ) = (2 + 4 +8+ 16 +32 +64+......)+( -1-2-4-8-16 -32 .........) = 63+.....

    • one year ago
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