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anas2000
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plz help
Mary thought of two numbers. She doubled her first number and trebled the second, added these two together and got 5. Then she multiplied her first number by four and added this to her second number. This time she got a result of 15. Find the first two numbers.
 2 years ago
 2 years ago
anas2000 Group Title
plz help Mary thought of two numbers. She doubled her first number and trebled the second, added these two together and got 5. Then she multiplied her first number by four and added this to her second number. This time she got a result of 15. Find the first two numbers.
 2 years ago
 2 years ago

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robert2 Group TitleBest ResponseYou've already chosen the best response.3
Okay, let's see if this works :P We'll call the first number x and the second y. 2x+3y=5 Then... 4x+y=15 To solve these you could put them onto a graph, by rewriting them. 3y=52x and y=154x Hopefully this should work! You should get 2 results for numbers on the x axis, which are your answers...
 2 years ago

anas2000 Group TitleBest ResponseYou've already chosen the best response.0
okay thanks
 2 years ago

DHASHNI Group TitleBest ResponseYou've already chosen the best response.0
thats right!
 2 years ago

Miyuru Group TitleBest ResponseYou've already chosen the best response.0
\[\text{Take it like this ..}\]\[\large\color{blue}{2x+3y=5}\]\[\large\color{green}{4x+y=15}\]\[\text{Now solve for x and y using substitution or any other method...}\]
 2 years ago

anas2000 Group TitleBest ResponseYou've already chosen the best response.0
are the answers 4 and 1
 2 years ago

Miyuru Group TitleBest ResponseYou've already chosen the best response.0
\[\text{You could do it like this..}\]\[4x+y=15\]\[x=\frac{15y}{4}\]Now substitute this..\[3y=52x\]\[3y=52(\frac{15y}{4})\]\[3y=5(\frac{15y}{2})\]\[6y=1015+y\]\[5y=5\]\[y=1\]\[\text{So to find x}\]\[x=\frac{15y}{4}\]\[x=\frac{15(1)}{4}\]\[x=\frac{16}{4}\]\[x=4\]
 2 years ago
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