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Mary thought of two numbers. She doubled her first number and trebled the second, added these two together and got 5. Then she multiplied her first number by four and added this to her second number. This time she got a result of 15. Find the first two numbers.
 one year ago
 one year ago
plz help Mary thought of two numbers. She doubled her first number and trebled the second, added these two together and got 5. Then she multiplied her first number by four and added this to her second number. This time she got a result of 15. Find the first two numbers.
 one year ago
 one year ago

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robert2Best ResponseYou've already chosen the best response.3
Okay, let's see if this works :P We'll call the first number x and the second y. 2x+3y=5 Then... 4x+y=15 To solve these you could put them onto a graph, by rewriting them. 3y=52x and y=154x Hopefully this should work! You should get 2 results for numbers on the x axis, which are your answers...
 one year ago

MiyuruBest ResponseYou've already chosen the best response.0
\[\text{Take it like this ..}\]\[\large\color{blue}{2x+3y=5}\]\[\large\color{green}{4x+y=15}\]\[\text{Now solve for x and y using substitution or any other method...}\]
 one year ago

anas2000Best ResponseYou've already chosen the best response.0
are the answers 4 and 1
 one year ago

MiyuruBest ResponseYou've already chosen the best response.0
\[\text{You could do it like this..}\]\[4x+y=15\]\[x=\frac{15y}{4}\]Now substitute this..\[3y=52x\]\[3y=52(\frac{15y}{4})\]\[3y=5(\frac{15y}{2})\]\[6y=1015+y\]\[5y=5\]\[y=1\]\[\text{So to find x}\]\[x=\frac{15y}{4}\]\[x=\frac{15(1)}{4}\]\[x=\frac{16}{4}\]\[x=4\]
 one year ago
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