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9

  • 3 years ago

please show ur Work >>>> Dimension of a pressure ?

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  1. 9
    • 3 years ago
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    i need to see the steps of solving it plz :)

  2. ash2326
    • 3 years ago
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    Do you know the relation between Pressure and force?

  3. 9
    • 3 years ago
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    i know \[p = \frac{ F }{ a }\] So \[= \frac{ m a }{a }\]

  4. ash2326
    • 3 years ago
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    \[P=ma / A\] \[a\ne A\] can you tell me the difference between a and A?

  5. 9
    • 3 years ago
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    idk , u tell me :B

  6. 9
    • 3 years ago
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    i just wanna know how we got L to the power -1 and T to the power -2

  7. 9
    • 3 years ago
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    how we got the negative powers ?

  8. ash2326
    • 3 years ago
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    a= acceleration= distance/ (time )^2= L/T^2=\(LT^{-2}\) A= area= \(L^2\)

  9. 9
    • 3 years ago
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    oh yeah

  10. ash2326
    • 3 years ago
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    Can you try now?

  11. 9
    • 3 years ago
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    gemme a minute

  12. ash2326
    • 3 years ago
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    sure :)

  13. 9
    • 3 years ago
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    = \[\frac{ M L T ^{-2} }{L T ^{-2} }\]

  14. 9
    • 3 years ago
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    is that right -0-

  15. ash2326
    • 3 years ago
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    Why you have \(Lt^{-2}\) in the denominator?

  16. 9
    • 3 years ago
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    because pressure = \[\frac{ m a }{a }\] and \[a = l T ^{-2}\]

  17. 9
    • 3 years ago
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    u just said that >_>

  18. ash2326
    • 3 years ago
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    Read my post again,

  19. 9
    • 3 years ago
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    is p pressure Force over area ?

  20. ash2326
    • 3 years ago
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    Yes :)

  21. 9
    • 3 years ago
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    i thought its force over acceleration -.-

  22. 9
    • 3 years ago
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    okie my bad

  23. ash2326
    • 3 years ago
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    No problem, you got it now?

  24. 9
    • 3 years ago
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    yeah -,- thanks again

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