Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

please show ur Work >>>> Dimension of a pressure ?

Physics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

i need to see the steps of solving it plz :)
Do you know the relation between Pressure and force?
i know \[p = \frac{ F }{ a }\] So \[= \frac{ m a }{a }\]

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

\[P=ma / A\] \[a\ne A\] can you tell me the difference between a and A?
idk , u tell me :B
i just wanna know how we got L to the power -1 and T to the power -2
how we got the negative powers ?
a= acceleration= distance/ (time )^2= L/T^2=\(LT^{-2}\) A= area= \(L^2\)
oh yeah
Can you try now?
gemme a minute
sure :)
= \[\frac{ M L T ^{-2} }{L T ^{-2} }\]
is that right -0-
Why you have \(Lt^{-2}\) in the denominator?
because pressure = \[\frac{ m a }{a }\] and \[a = l T ^{-2}\]
u just said that >_>
Read my post again,
is p pressure Force over area ?
Yes :)
i thought its force over acceleration -.-
okie my bad
No problem, you got it now?
yeah -,- thanks again

Not the answer you are looking for?

Search for more explanations.

Ask your own question