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anonymous
 4 years ago
please show ur Work >>>>
Dimension of a pressure ?
anonymous
 4 years ago
please show ur Work >>>> Dimension of a pressure ?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i need to see the steps of solving it plz :)

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.1Do you know the relation between Pressure and force?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i know \[p = \frac{ F }{ a }\] So \[= \frac{ m a }{a }\]

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.1\[P=ma / A\] \[a\ne A\] can you tell me the difference between a and A?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i just wanna know how we got L to the power 1 and T to the power 2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how we got the negative powers ?

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.1a= acceleration= distance/ (time )^2= L/T^2=\(LT^{2}\) A= area= \(L^2\)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0= \[\frac{ M L T ^{2} }{L T ^{2} }\]

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.1Why you have \(Lt^{2}\) in the denominator?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0because pressure = \[\frac{ m a }{a }\] and \[a = l T ^{2}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is p pressure Force over area ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i thought its force over acceleration .

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.1No problem, you got it now?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah , thanks again
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