anonymous
  • anonymous
please show ur Work >>>> Dimension of a pressure ?
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
i need to see the steps of solving it plz :)
ash2326
  • ash2326
Do you know the relation between Pressure and force?
anonymous
  • anonymous
i know \[p = \frac{ F }{ a }\] So \[= \frac{ m a }{a }\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

ash2326
  • ash2326
\[P=ma / A\] \[a\ne A\] can you tell me the difference between a and A?
anonymous
  • anonymous
idk , u tell me :B
anonymous
  • anonymous
i just wanna know how we got L to the power -1 and T to the power -2
anonymous
  • anonymous
how we got the negative powers ?
ash2326
  • ash2326
a= acceleration= distance/ (time )^2= L/T^2=\(LT^{-2}\) A= area= \(L^2\)
anonymous
  • anonymous
oh yeah
ash2326
  • ash2326
Can you try now?
anonymous
  • anonymous
gemme a minute
ash2326
  • ash2326
sure :)
anonymous
  • anonymous
= \[\frac{ M L T ^{-2} }{L T ^{-2} }\]
anonymous
  • anonymous
is that right -0-
ash2326
  • ash2326
Why you have \(Lt^{-2}\) in the denominator?
anonymous
  • anonymous
because pressure = \[\frac{ m a }{a }\] and \[a = l T ^{-2}\]
anonymous
  • anonymous
u just said that >_>
ash2326
  • ash2326
Read my post again,
anonymous
  • anonymous
is p pressure Force over area ?
ash2326
  • ash2326
Yes :)
anonymous
  • anonymous
i thought its force over acceleration -.-
anonymous
  • anonymous
okie my bad
ash2326
  • ash2326
No problem, you got it now?
anonymous
  • anonymous
yeah -,- thanks again

Looking for something else?

Not the answer you are looking for? Search for more explanations.