Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Goten77

  • 3 years ago

y=xln(x) y1=1+lnx if i want the criticle points then i set 1+lnx=0 but how do you do this or am i wrong on something?

  • This Question is Closed
  1. Algebraic!
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    y1=1+lnx what's that?

  2. Goten77
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1352398609788:dw|

  3. Algebraic!
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    ok, that's fine then..

  4. Algebraic!
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    ln(x) =-1 x=e^-1

  5. Goten77
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yee im starting to get it now... basically e^-1 since the base is e and the other side is -1

  6. Algebraic!
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yes, exactly.

  7. Goten77
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    this makes sense now.. idk y i couldnt think of this b4 on the quiz....

  8. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy