y=xe^(-x/8) y1=x(e^(-x/8))(-1/8) + e^(-x/8)(1) critical points ima type this below along w/ the question

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

y=xe^(-x/8) y1=x(e^(-x/8))(-1/8) + e^(-x/8)(1) critical points ima type this below along w/ the question

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

\[y=xe ^{-x/8}\] then derivative is this correct? \[y ^{1}=xe ^{-x/8}(-1/8) + e ^{-x/8}1\]
simplifying your 1st derivative you will have \[\frac{dy}{dx} = e^{-\frac{x}{8}}(-\frac{1}{8} x + 1)\] so you need to solve \[-\frac{1}{8} x + 1 = 0\]
ok thats what i got and then i get like -1/8x = -1 then x=-1/(-1/8) = +8

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

thats correct.... that is the only value of x that makes the 1st derivative = 0...
oh nvm i c y e^o=1 eh i aint thinking
if you have x = 0 then \[dy/dx = e^{-\frac{0}{8}}(-\frac{1}{8}\times 0 + 1) = 1\] because \[e^{\frac{0}{8}} = 1\] any number to a power of zero is 1 so only 1 critical point...
man i made so many simple mistakes on this last quiz... today i just aint thinking... oh well atleast i got this concept right XD

Not the answer you are looking for?

Search for more explanations.

Ask your own question