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 one year ago
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furnessjBest ResponseYou've already chosen the best response.0
do you have answers to check?
 one year ago

ksaimouliBest ResponseYou've already chosen the best response.1
i did a y=112 initial velocity
 one year ago

ksaimouliBest ResponseYou've already chosen the best response.1
dw:1352405626465:dw
 one year ago

furnessjBest ResponseYou've already chosen the best response.0
sorry i didn't look at the second page. First equation is simple: v = v_o +at 0 = 112 +(g)t now, you need to change feet into metres to use 9.81 for g 112 / 3.28 = 34.146 so 34.146 / 9.81 = t
 one year ago

furnessjBest ResponseYou've already chosen the best response.0
Second part: you are only worried about horizontal velocity (no air resistance), the up and down plays no part here. So simply: horizontal distance = horizontal speed x time hd = 224cos30 x 7
 one year ago

ksaimouliBest ResponseYou've already chosen the best response.1
instead of v=v0 cani use v=v0t+1/2gt^2
 one year ago

furnessjBest ResponseYou've already chosen the best response.0
no, that equation is s = v0t + 1/2gt^2, and s is displacement, which we don't know yet
 one year ago
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