Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
ksaimouli
Group Title
 2 years ago
 2 years ago
ksaimouli Group Title
 2 years ago
 2 years ago

This Question is Closed

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
in that b and c
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
@furnessj
 2 years ago

furnessj Group TitleBest ResponseYou've already chosen the best response.0
do you have answers to check?
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
check bottom page
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
i did a y=112 initial velocity
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
y=vit4.9t^2
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
dw:1352405626465:dw
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
is that right
 2 years ago

furnessj Group TitleBest ResponseYou've already chosen the best response.0
sorry i didn't look at the second page. First equation is simple: v = v_o +at 0 = 112 +(g)t now, you need to change feet into metres to use 9.81 for g 112 / 3.28 = 34.146 so 34.146 / 9.81 = t
 2 years ago

furnessj Group TitleBest ResponseYou've already chosen the best response.0
Second part: you are only worried about horizontal velocity (no air resistance), the up and down plays no part here. So simply: horizontal distance = horizontal speed x time hd = 224cos30 x 7
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
instead of v=v0 cani use v=v0t+1/2gt^2
 2 years ago

furnessj Group TitleBest ResponseYou've already chosen the best response.0
no, that equation is s = v0t + 1/2gt^2, and s is displacement, which we don't know yet
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.