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help_needed

  • 2 years ago

Find the linearization L(x) of the function at a. f(x) = x^4 + 4x^2, a = −1

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  1. help_needed
    • 2 years ago
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    I keep getting F(x) = f(x) = -12x - 8 as my asnwer but it's wrong :(

  2. mukushla
    • 2 years ago
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    is this right? \[L(x)=f(a)+(x-a)f'(a) \]

  3. help_needed
    • 2 years ago
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    yes

  4. mukushla
    • 2 years ago
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    so we have a=-1 and\[L(x)=f(-1)+(x+1)f'(-1)\]how about this one ? make sense?

  5. mukushla
    • 2 years ago
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    i think u got it from here :)

  6. help_needed
    • 2 years ago
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    yeah but thats exactly what i do but the asnwer sumhow is wrong

  7. help_needed
    • 2 years ago
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    f(-1) = 5 and f'(-1) = -12. So it becomes 5 + -12(x+1) = -12x + 8

  8. help_needed
    • 2 years ago
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    and it keeps marking it wrong

  9. help_needed
    • 2 years ago
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    idk what im doing wrong here

  10. mukushla
    • 2 years ago
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    lemme check

  11. help_needed
    • 2 years ago
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    srry that shud be -12x -8

  12. mukushla
    • 2 years ago
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    i got ... -12x-7

  13. help_needed
    • 2 years ago
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    WOWW IM SUCHHH A FAILLURE...OK wow i cant beleive i got the calc right and algebra wrong

  14. help_needed
    • 2 years ago
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    thank u lol i really cant beleive i got this wrong

  15. mukushla
    • 2 years ago
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    no problem ..it happens sometime :)

  16. help_needed
    • 2 years ago
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    ok but this one its not about the algebra. Im just cnfused how to do it. Do u mind helping if i post it

  17. mukushla
    • 2 years ago
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    ah sure :)

  18. help_needed
    • 2 years ago
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    Thanks im posting it as a dffnt question

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spraguer (Moderator)
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