anonymous
  • anonymous
Find the linearization L(x) of the function at a. f(x) = x^4 + 4x^2, a = −1
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
I keep getting F(x) = f(x) = -12x - 8 as my asnwer but it's wrong :(
anonymous
  • anonymous
is this right? \[L(x)=f(a)+(x-a)f'(a) \]
anonymous
  • anonymous
yes

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anonymous
  • anonymous
so we have a=-1 and\[L(x)=f(-1)+(x+1)f'(-1)\]how about this one ? make sense?
anonymous
  • anonymous
i think u got it from here :)
anonymous
  • anonymous
yeah but thats exactly what i do but the asnwer sumhow is wrong
anonymous
  • anonymous
f(-1) = 5 and f'(-1) = -12. So it becomes 5 + -12(x+1) = -12x + 8
anonymous
  • anonymous
and it keeps marking it wrong
anonymous
  • anonymous
idk what im doing wrong here
anonymous
  • anonymous
lemme check
anonymous
  • anonymous
srry that shud be -12x -8
anonymous
  • anonymous
i got ... -12x-7
anonymous
  • anonymous
WOWW IM SUCHHH A FAILLURE...OK wow i cant beleive i got the calc right and algebra wrong
anonymous
  • anonymous
thank u lol i really cant beleive i got this wrong
anonymous
  • anonymous
no problem ..it happens sometime :)
anonymous
  • anonymous
ok but this one its not about the algebra. Im just cnfused how to do it. Do u mind helping if i post it
anonymous
  • anonymous
ah sure :)
anonymous
  • anonymous
Thanks im posting it as a dffnt question

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