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Find the linearization L(x) of the function at a.
f(x) = x^4 + 4x^2, a = −1
 one year ago
 one year ago
Find the linearization L(x) of the function at a. f(x) = x^4 + 4x^2, a = −1
 one year ago
 one year ago

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help_neededBest ResponseYou've already chosen the best response.0
I keep getting F(x) = f(x) = 12x  8 as my asnwer but it's wrong :(
 one year ago

mukushlaBest ResponseYou've already chosen the best response.1
is this right? \[L(x)=f(a)+(xa)f'(a) \]
 one year ago

mukushlaBest ResponseYou've already chosen the best response.1
so we have a=1 and\[L(x)=f(1)+(x+1)f'(1)\]how about this one ? make sense?
 one year ago

mukushlaBest ResponseYou've already chosen the best response.1
i think u got it from here :)
 one year ago

help_neededBest ResponseYou've already chosen the best response.0
yeah but thats exactly what i do but the asnwer sumhow is wrong
 one year ago

help_neededBest ResponseYou've already chosen the best response.0
f(1) = 5 and f'(1) = 12. So it becomes 5 + 12(x+1) = 12x + 8
 one year ago

help_neededBest ResponseYou've already chosen the best response.0
and it keeps marking it wrong
 one year ago

help_neededBest ResponseYou've already chosen the best response.0
idk what im doing wrong here
 one year ago

help_neededBest ResponseYou've already chosen the best response.0
srry that shud be 12x 8
 one year ago

help_neededBest ResponseYou've already chosen the best response.0
WOWW IM SUCHHH A FAILLURE...OK wow i cant beleive i got the calc right and algebra wrong
 one year ago

help_neededBest ResponseYou've already chosen the best response.0
thank u lol i really cant beleive i got this wrong
 one year ago

mukushlaBest ResponseYou've already chosen the best response.1
no problem ..it happens sometime :)
 one year ago

help_neededBest ResponseYou've already chosen the best response.0
ok but this one its not about the algebra. Im just cnfused how to do it. Do u mind helping if i post it
 one year ago

help_neededBest ResponseYou've already chosen the best response.0
Thanks im posting it as a dffnt question
 one year ago
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