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ok u just need a linear approximation of \(e^x\)

So I should still use the f(a) + f'(a) (x-a) ?

yes and u have\[f(x)=e^x\]and \[a=\text{whatever u want but better and simpler to use 0} \]

ok so let me try this to see what equation i get

iDK if what i did makes sense. I got f(0) + f'(o)(x-0) = 1 + 0(x-0) = 1

emm but f'(0) is 1 ha?

f'(x) = 1/x right so isnt x=0 so that makes it 1/0 = 0.

f'(x)=e^x

i gotta go...good night from eastern hemisphere :) think about it.

ok tahnks!

bye and thank u

Its 3:35 pm here in the USA! but gnite