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help_needed

  • 3 years ago

Use a linear approximation (or differentials) to estimate the given number. e^0.01

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  1. mukushla
    • 3 years ago
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    ok u just need a linear approximation of \(e^x\)

  2. help_needed
    • 3 years ago
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    So I should still use the f(a) + f'(a) (x-a) ?

  3. mukushla
    • 3 years ago
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    yes and u have\[f(x)=e^x\]and \[a=\text{whatever u want but better and simpler to use 0} \]

  4. help_needed
    • 3 years ago
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    ok so let me try this to see what equation i get

  5. help_needed
    • 3 years ago
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    iDK if what i did makes sense. I got f(0) + f'(o)(x-0) = 1 + 0(x-0) = 1

  6. mukushla
    • 3 years ago
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    emm but f'(0) is 1 ha?

  7. help_needed
    • 3 years ago
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    f'(x) = 1/x right so isnt x=0 so that makes it 1/0 = 0.

  8. mukushla
    • 3 years ago
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    f'(x)=e^x

  9. mukushla
    • 3 years ago
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    i gotta go...good night from eastern hemisphere :) think about it.

  10. help_needed
    • 3 years ago
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    ok tahnks!

  11. help_needed
    • 3 years ago
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    bye and thank u

  12. help_needed
    • 3 years ago
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    Its 3:35 pm here in the USA! but gnite

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