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help_needed
Group Title
Use a linear approximation (or differentials) to estimate the given number.
e^0.01
 one year ago
 one year ago
help_needed Group Title
Use a linear approximation (or differentials) to estimate the given number. e^0.01
 one year ago
 one year ago

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mukushla Group TitleBest ResponseYou've already chosen the best response.1
ok u just need a linear approximation of \(e^x\)
 one year ago

help_needed Group TitleBest ResponseYou've already chosen the best response.0
So I should still use the f(a) + f'(a) (xa) ?
 one year ago

mukushla Group TitleBest ResponseYou've already chosen the best response.1
yes and u have\[f(x)=e^x\]and \[a=\text{whatever u want but better and simpler to use 0} \]
 one year ago

help_needed Group TitleBest ResponseYou've already chosen the best response.0
ok so let me try this to see what equation i get
 one year ago

help_needed Group TitleBest ResponseYou've already chosen the best response.0
iDK if what i did makes sense. I got f(0) + f'(o)(x0) = 1 + 0(x0) = 1
 one year ago

mukushla Group TitleBest ResponseYou've already chosen the best response.1
emm but f'(0) is 1 ha?
 one year ago

help_needed Group TitleBest ResponseYou've already chosen the best response.0
f'(x) = 1/x right so isnt x=0 so that makes it 1/0 = 0.
 one year ago

mukushla Group TitleBest ResponseYou've already chosen the best response.1
f'(x)=e^x
 one year ago

mukushla Group TitleBest ResponseYou've already chosen the best response.1
i gotta go...good night from eastern hemisphere :) think about it.
 one year ago

help_needed Group TitleBest ResponseYou've already chosen the best response.0
ok tahnks!
 one year ago

help_needed Group TitleBest ResponseYou've already chosen the best response.0
bye and thank u
 one year ago

help_needed Group TitleBest ResponseYou've already chosen the best response.0
Its 3:35 pm here in the USA! but gnite
 one year ago
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