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 2 years ago
HELP! Liquid ammonia boils at –33.4ºC and has a heat of vaporization of 23.5 kJ/mol. What is its vapor pressure at –50.0ºC? (R = 8.314 J/K•mol)
 2 years ago
HELP! Liquid ammonia boils at –33.4ºC and has a heat of vaporization of 23.5 kJ/mol. What is its vapor pressure at –50.0ºC? (R = 8.314 J/K•mol)

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jennilalala
 2 years ago
Best ResponseYou've already chosen the best response.1ln (P1 / P2) =  (ΔH / R) (1/T1  1/T2)

jennilalala
 2 years ago
Best ResponseYou've already chosen the best response.1solve for p1. change of H is 23.5

jennilalala
 2 years ago
Best ResponseYou've already chosen the best response.1the vapor pressure of a substance at its normal boiling point is 760 mmHg

jennilalala
 2 years ago
Best ResponseYou've already chosen the best response.1so use that as your p2 @bs46shal
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