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HelpMe94

  • 2 years ago

Add and Simplify (cos(x)/Sin(x))+(Sin(x)/Cos(x))

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  1. mark_o.
    • 2 years ago
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    whats our common denominator? sin cos x right? can you try to continue? cos x sin x ----- + ------ = ------------ sin x cos x sin x cos x

  2. HelpMe94
    • 2 years ago
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    |dw:1352421024901:dw|

  3. HelpMe94
    • 2 years ago
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    \[\cos x \sin ^{2}x \times \frac{ 1 }{ \sin x \cos x }\]

  4. mark_o.
    • 2 years ago
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    cos x sin x cos x(cos x) +sin x(sin x) ----- + ------ = ---------------------------- sin x cos x sin x cos x

  5. HelpMe94
    • 2 years ago
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    oh oops forgot to multiply both fractions

  6. HelpMe94
    • 2 years ago
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    |dw:1352421346060:dw|

  7. HelpMe94
    • 2 years ago
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    |dw:1352421430067:dw|

  8. HelpMe94
    • 2 years ago
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    |dw:1352421617501:dw|

  9. mark_o.
    • 2 years ago
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    alternate solution multiply them with something that will make a common denominator we wanted to have a common denominator of sin x cos x therefore cos x cos x sin x sin x (cos x )^2 + (sin x)^2 1 ----- . ------- + ------ .----- = ------------------------ = ------------ sin x cos x cos x sin x sin x cos x sin x cos x whats 1/sin x =? also 1/cos x ?

  10. HelpMe94
    • 2 years ago
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    |dw:1352421796900:dw|

  11. HelpMe94
    • 2 years ago
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    So the answer is CSC(X)SEC(X)

  12. mark_o.
    • 2 years ago
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    yesss 1 1 1 csc x sec x = ----------- = -------- --------- or = ------- or = ------ or= csc x sec x sin x cos x sin x cos x cos x sin x

  13. HelpMe94
    • 2 years ago
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    Although i don't see how you get COS(X)^2 + SIN(X)^2 1 ----------------- = --------------- SIN(X) COS(X) SIN(X) COS(X)

  14. mark_o.
    • 2 years ago
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    isnt it the identity (sin x)^2 + (cos x)^2 = 1 ??

  15. HelpMe94
    • 2 years ago
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    oh yeah your right

  16. HelpMe94
    • 2 years ago
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    Thanks again

  17. mark_o.
    • 2 years ago
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    ok = 1/ sin x cos x = csc x/ cos x = sec x / sin x = sec x csc x

  18. mark_o.
    • 2 years ago
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    yw... have fun now solving.. :D poist some more if you got stuck again :D

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