find an equation of the line passing through the point (2,3) and parallel to the line 3x+4y-8=0

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find an equation of the line passing through the point (2,3) and parallel to the line 3x+4y-8=0

Mathematics
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given point (2,3) and the line 3x+4y-8=0 first we want to simplify 3x+4y-8=0 to 4y= -3x + 8 y = -(3/4)x + 2 since this is parallel to the line we wanted its slope m is the same whats the slope m= ?
the slope is -3/4
if thats the slope we can use it to form equation of the line using the formula and the point (2,3) y-y1=m(x - x1) try forming it using this formula

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Other answers:

y-3=-3/4(x-2)
yesss... now you can rearrange your answer to slope intercept form
that is where I get lost
ah ok, try to rearrange it to slope intercept form
so everything is alright now? :D have fun solving now... :D

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