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in a 1 litre vessel at 1000k are introduced 0.1 mole each of NO and Br2 and 0.01 mole of NOBr
2NO(g)+Br2(g)=2NOBr(g)
Kc=1.32*10^2
determine the direction of the net reaction and calculate the partial pressure of NOBr in the vessel at equilibrium?
 one year ago
 one year ago
in a 1 litre vessel at 1000k are introduced 0.1 mole each of NO and Br2 and 0.01 mole of NOBr 2NO(g)+Br2(g)=2NOBr(g) Kc=1.32*10^2 determine the direction of the net reaction and calculate the partial pressure of NOBr in the vessel at equilibrium?
 one year ago
 one year ago

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Ruchi.Best ResponseYou've already chosen the best response.0
@UnkleRhaukus @timo86m @ghazi
 one year ago

ghaziBest ResponseYou've already chosen the best response.2
\[K _{p}=\frac{ P _{NoBr} }{ [P _{NO}]*[P _{Br2}] }\]
 one year ago

ghaziBest ResponseYou've already chosen the best response.2
and use Kp and Kc relation before this
 one year ago

Ruchi.Best ResponseYou've already chosen the best response.0
bt by this i will nt gt the answer.
 one year ago

ghaziBest ResponseYou've already chosen the best response.2
\[Kp=Kc*(RT)^{\Delta n}\]
 one year ago

ghaziBest ResponseYou've already chosen the best response.2
now to find Kc you have been provided with everything
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
i can not do these
 one year ago

him1618Best ResponseYou've already chosen the best response.0
Find out the reaction quotient
 one year ago

Ruchi.Best ResponseYou've already chosen the best response.0
reaction quotient? i'm nt getting wati t mean
 one year ago

him1618Best ResponseYou've already chosen the best response.0
(NOBr)^2 / (NO)^2 * (Br2)
 one year ago

him1618Best ResponseYou've already chosen the best response.0
if its greater than kc, move backward, less than means forward
 one year ago

him1618Best ResponseYou've already chosen the best response.0
pressure i dunno how to do
 one year ago

him1618Best ResponseYou've already chosen the best response.0
i dont know the pressure part
 one year ago

timo86mBest ResponseYou've already chosen the best response.0
oh sorry i wouldn't know
 one year ago

Ruchi.Best ResponseYou've already chosen the best response.0
@TuringTest can u hlp me out
 one year ago
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