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anonymous
 4 years ago
in a 1 litre vessel at 1000k are introduced 0.1 mole each of NO and Br2 and 0.01 mole of NOBr
2NO(g)+Br2(g)=2NOBr(g)
Kc=1.32*10^2
determine the direction of the net reaction and calculate the partial pressure of NOBr in the vessel at equilibrium?
anonymous
 4 years ago
in a 1 litre vessel at 1000k are introduced 0.1 mole each of NO and Br2 and 0.01 mole of NOBr 2NO(g)+Br2(g)=2NOBr(g) Kc=1.32*10^2 determine the direction of the net reaction and calculate the partial pressure of NOBr in the vessel at equilibrium?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@UnkleRhaukus @timo86m @ghazi

Ghazi
 4 years ago
Best ResponseYou've already chosen the best response.2\[K _{p}=\frac{ P _{NoBr} }{ [P _{NO}]*[P _{Br2}] }\]

Ghazi
 4 years ago
Best ResponseYou've already chosen the best response.2and use Kp and Kc relation before this

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0bt by this i will nt gt the answer.

Ghazi
 4 years ago
Best ResponseYou've already chosen the best response.2\[Kp=Kc*(RT)^{\Delta n}\]

Ghazi
 4 years ago
Best ResponseYou've already chosen the best response.2now to find Kc you have been provided with everything

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@DLS can u hlp me out

UnkleRhaukus
 4 years ago
Best ResponseYou've already chosen the best response.0i can not do these

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Find out the reaction quotient

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0reaction quotient? i'm nt getting wati t mean

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0(NOBr)^2 / (NO)^2 * (Br2)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if its greater than kc, move backward, less than means forward

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0pressure i dunno how to do

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i dont know the pressure part

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh sorry i wouldn't know

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@TuringTest can u hlp me out
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