## anonymous 3 years ago I have the points (5,1) and (-3, 4) I have to put them in Slope Intercept, Point-Slope, and Standard form. I got Point-Slope. ( y - 1 = 3/8(x - 5) but I can't figure out the other two for the life of me! Anyone?

1. anonymous

Point slope form is: $y-y_{1}=m(x-x_{1})$ Standard form is: $Ax+By=C$ Slope intercept form is: $y=mx+b$

2. anonymous

I know, I tried to work them out but the 3/8 is throwing me off. I've been working on this for over two hours now. :/ I used Khanacademy but his problems all came out even, which this won't and I'm scared to veer too far away from what I know that I'll mess it up.

3. anonymous

i need help can u help me

4. anonymous

Depends on what you need help with?

5. anonymous

6. anonymous

I get y-1=-3/8(x-5)

7. anonymous

It might be wrong? That was just the slope I came up with, both ways.

8. anonymous

To find the slope intercept form multiply -3/8 through (x-5) -3/8(x) is easy to figure out what -3/8(5) is, put the 5 in a fraction form then multiply straight across. $(\frac{ -3 }{ 8 })(\frac{ 5 }{ 1 })=?$

9. anonymous

You should get -3/8x-(-15/8) or -3/8x+15/8 now add the one from the left side to the right side 1+15/8 find a common denominator first then add 8/8+15/8= 23/8 y=-3/8x +23/8 slope intercept form to get standard form just add 3/8x to the left side 3/8x +y = 23/8

10. anonymous

Thank you soo much!

11. anonymous

But wait, if you add 3/8x to one side don't you have to do it to the other as well?

12. anonymous

It seems like you can just leave it 3/8x + y = 23/8

13. anonymous

adding 3/8x to the left will cancel it out on the right

14. anonymous

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15. anonymous

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