Here's the question you clicked on:
HelpMe94
Verify SEC(X) CSC(X) ----------- = COT(X) TAN(X) Please Help SIN(X) COS(X) Explain Steps
\[\frac{ SEC(X) CSC(X) }{ SIN(X)COS(X) }=COT(X)TAN(X)\] Verify This Explain
This is the solution by how did it get from line 1 to line 2
\[\frac{ 1 }{ SIN(X)COS(X) } \to \frac{ COS(X)^{2} + SIN(X)^{2}}{ SIN(X)COS(X)}\]
The question is wrong. The RHS gives 1 whereas the LHS is 1/(sinx*cosx)^2
@mark_o. Can you help me again?
i don;t understand how is the question wrong?
Because the LHS is not equal to the RHS. I think the question is sec(x)cos(x)/sin(x)csc(x) =tan(x)cot(c)
i moved this http://openstudy.com/updates/509c8db9e4b0a825f21b1cf9