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HelpMe94

  • 2 years ago

Verify SEC(X) CSC(X) ----------- = COT(X) TAN(X) Please Help SIN(X) COS(X) Explain Steps

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  1. HelpMe94
    • 2 years ago
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    \[\frac{ SEC(X) CSC(X) }{ SIN(X)COS(X) }=COT(X)TAN(X)\] Verify This Explain

  2. HelpMe94
    • 2 years ago
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    This is the solution by how did it get from line 1 to line 2

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  3. HelpMe94
    • 2 years ago
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    \[\frac{ 1 }{ SIN(X)COS(X) } \to \frac{ COS(X)^{2} + SIN(X)^{2}}{ SIN(X)COS(X)}\]

  4. Varuns
    • 2 years ago
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    The question is wrong. The RHS gives 1 whereas the LHS is 1/(sinx*cosx)^2

  5. HelpMe94
    • 2 years ago
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    @mark_o. Can you help me again?

  6. HelpMe94
    • 2 years ago
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    i don;t understand how is the question wrong?

  7. Varuns
    • 2 years ago
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    Because the LHS is not equal to the RHS. I think the question is sec(x)cos(x)/sin(x)csc(x) =tan(x)cot(c)

  8. HelpMe94
    • 2 years ago
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    no

  9. HelpMe94
    • 2 years ago
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    i moved this http://openstudy.com/updates/509c8db9e4b0a825f21b1cf9

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