A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

ChemicallyWrit
 2 years ago
Best ResponseYou've already chosen the best response.0A 50.0 kg sprinter, starting from rest, runs 55.0m in 9.80s at constant acceleration. I figured I'd have to use a kinematic equation for this: 55=0+0(9.8)+a(9.8^2) And then I could multiply by the mass, and I'd have my force. But this doesn't seem to be working. It would help, I suppose, if I could figure out what all the forces are.

ninjin
 2 years ago
Best ResponseYou've already chosen the best response.0what are you trying to find?

gerryliyana
 2 years ago
Best ResponseYou've already chosen the best response.3A 50.0 kg sprinter, starting from rest, runs 55.0m in 9.80s at constant acceleration. I figured I'd have to use a kinematic equation for this: SO to finding horizontal force: s = vo t + 0.5 a t^2 s = 0 + 0.5 a t^2 s = 0.5 a t^2 a = s/(0.5 t^2) a = 55 / (0.5 x (9.8^2)) a = 55/48.02 a =1.145 m/s^2 F = ma F = 50 kg x 1.145 m/s^2 F = 57.267 N

ChemicallyWrit
 2 years ago
Best ResponseYou've already chosen the best response.0Thanks again! You're like a physics ninja. ^^

gerryliyana
 2 years ago
Best ResponseYou've already chosen the best response.3ur welcome @ChemicallyWrit happy to help u :)
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.