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anonymous
 4 years ago
I'm having trouble finding horizontal force. More info in comment.
anonymous
 4 years ago
I'm having trouble finding horizontal force. More info in comment.

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0A 50.0 kg sprinter, starting from rest, runs 55.0m in 9.80s at constant acceleration. I figured I'd have to use a kinematic equation for this: 55=0+0(9.8)+a(9.8^2) And then I could multiply by the mass, and I'd have my force. But this doesn't seem to be working. It would help, I suppose, if I could figure out what all the forces are.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what are you trying to find?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0A 50.0 kg sprinter, starting from rest, runs 55.0m in 9.80s at constant acceleration. I figured I'd have to use a kinematic equation for this: SO to finding horizontal force: s = vo t + 0.5 a t^2 s = 0 + 0.5 a t^2 s = 0.5 a t^2 a = s/(0.5 t^2) a = 55 / (0.5 x (9.8^2)) a = 55/48.02 a =1.145 m/s^2 F = ma F = 50 kg x 1.145 m/s^2 F = 57.267 N

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thanks again! You're like a physics ninja. ^^

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ur welcome @ChemicallyWrit happy to help u :)
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