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ChemicallyWrit
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I'm having trouble finding horizontal force. More info in comment.
 one year ago
 one year ago
ChemicallyWrit Group Title
I'm having trouble finding horizontal force. More info in comment.
 one year ago
 one year ago

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ChemicallyWrit Group TitleBest ResponseYou've already chosen the best response.0
A 50.0 kg sprinter, starting from rest, runs 55.0m in 9.80s at constant acceleration. I figured I'd have to use a kinematic equation for this: 55=0+0(9.8)+a(9.8^2) And then I could multiply by the mass, and I'd have my force. But this doesn't seem to be working. It would help, I suppose, if I could figure out what all the forces are.
 one year ago

ninjin Group TitleBest ResponseYou've already chosen the best response.0
what are you trying to find?
 one year ago

gerryliyana Group TitleBest ResponseYou've already chosen the best response.3
A 50.0 kg sprinter, starting from rest, runs 55.0m in 9.80s at constant acceleration. I figured I'd have to use a kinematic equation for this: SO to finding horizontal force: s = vo t + 0.5 a t^2 s = 0 + 0.5 a t^2 s = 0.5 a t^2 a = s/(0.5 t^2) a = 55 / (0.5 x (9.8^2)) a = 55/48.02 a =1.145 m/s^2 F = ma F = 50 kg x 1.145 m/s^2 F = 57.267 N
 one year ago

ChemicallyWrit Group TitleBest ResponseYou've already chosen the best response.0
Thanks again! You're like a physics ninja. ^^
 one year ago

gerryliyana Group TitleBest ResponseYou've already chosen the best response.3
ur welcome @ChemicallyWrit happy to help u :)
 one year ago
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