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## anonymous 3 years ago \frac{ SEC(X) CSC(X) }{ SIN(X)COS(X) }=COT(X)TAN(X) Verify This..

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1. anonymous

$\frac{ SEC(X) CSC(X) }{ SIN(X)COS(X) }=COT(X)TAN(X)$

2. anonymous

Answer

3. anonymous

$\frac{ 1 }{ SIN(X)COS(X) } \to \frac{ COS(X)^{2} + SIN(X)^{2}}{ SIN(X)COS(X)}$ how do you get to this?

4. anonymous

cos(x)^2 + sin(x)^2 = 1 thats an identity

5. anonymous

oh

6. anonymous

ok i get that problem now but a new question $\tan (X+\frac{ \pi }{ 2 }) = - COT(X)$

7. anonymous

i used the sum of differences then i saw $\tan \frac{ \pi }{ 2 }=Undefined$

8. anonymous

sorry im not sure i can help you with just, you should close this question and ask it again so other people may help you

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