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anonymous
 3 years ago
\frac{ SEC(X) CSC(X) }{ SIN(X)COS(X) }=COT(X)TAN(X) Verify This..
anonymous
 3 years ago
\frac{ SEC(X) CSC(X) }{ SIN(X)COS(X) }=COT(X)TAN(X) Verify This..

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ SEC(X) CSC(X) }{ SIN(X)COS(X) }=COT(X)TAN(X)\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ 1 }{ SIN(X)COS(X) } \to \frac{ COS(X)^{2} + SIN(X)^{2}}{ SIN(X)COS(X)}\] how do you get to this?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0cos(x)^2 + sin(x)^2 = 1 thats an identity

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok i get that problem now but a new question \[\tan (X+\frac{ \pi }{ 2 }) =  COT(X)\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i used the sum of differences then i saw \[\tan \frac{ \pi }{ 2 }=Undefined\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0sorry im not sure i can help you with just, you should close this question and ask it again so other people may help you
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