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HelpMe94

  • 3 years ago

\frac{ SEC(X) CSC(X) }{ SIN(X)COS(X) }=COT(X)TAN(X) Verify This..

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  1. HelpMe94
    • 3 years ago
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    \[\frac{ SEC(X) CSC(X) }{ SIN(X)COS(X) }=COT(X)TAN(X)\]

  2. HelpMe94
    • 3 years ago
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  3. HelpMe94
    • 3 years ago
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    \[\frac{ 1 }{ SIN(X)COS(X) } \to \frac{ COS(X)^{2} + SIN(X)^{2}}{ SIN(X)COS(X)}\] how do you get to this?

  4. jayz657
    • 3 years ago
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    cos(x)^2 + sin(x)^2 = 1 thats an identity

  5. HelpMe94
    • 3 years ago
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    oh

  6. HelpMe94
    • 3 years ago
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    ok i get that problem now but a new question \[\tan (X+\frac{ \pi }{ 2 }) = - COT(X)\]

  7. HelpMe94
    • 3 years ago
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    i used the sum of differences then i saw \[\tan \frac{ \pi }{ 2 }=Undefined\]

  8. jayz657
    • 3 years ago
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    sorry im not sure i can help you with just, you should close this question and ask it again so other people may help you

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