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## iheartfood 3 years ago determine...

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1. iheartfood

|dw:1352440875600:dw|

2. iheartfood

***Please show work! :) thanks :)

3. jim_thompson5910

vertical asymptote: set the denominator equal to zero and solve for x

4. iheartfood

so x=-4 ?

5. jim_thompson5910

yes, that's the vertical asymptote

6. iheartfood

so how do i write it out?? VERTICAL ASYMPTOTE: x+4=0 -4 -4 x=-4 thats the equation of the VERTICAL asymptote?

7. jim_thompson5910

now long divide 3x^2 - 12 into x - 4

8. iheartfood

is that how i write it out with the work?

9. jim_thompson5910

yes

10. iheartfood

okay, so are there any oblique, horizontal or etc. asypmtotes?

11. jim_thompson5910

the degrees of the numerator and denominator are different (and the numerator degree is larger), so we have an oblique asymptote

12. iheartfood

kk how do i find that?

13. jim_thompson5910

long divide 3x^2 - 12 into x-4

14. iheartfood

|dw:1352441492481:dw|

15. iheartfood

|dw:1352441542380:dw| is that right??

16. jim_thompson5910

good only focus on the quotient

17. jim_thompson5910

so the oblique asymptote is y = 3x+12

18. iheartfood

oh so i just show the work i got above (disregarding the remainder) and my answer is y=3x+12 ?

19. jim_thompson5910

yep

20. iheartfood

oh wait, why is it divided by x-4?

21. iheartfood

and not x+4?

22. jim_thompson5910

hmm i for some reason thought it was x-4, my bad

23. iheartfood

so its x+4 ?

24. jim_thompson5910

yeah sry

25. iheartfood

okay so i get this?|dw:1352442040613:dw|

26. iheartfood

so my answer is y=3x-12?

27. jim_thompson5910

you got it

28. iheartfood

yayy!! and are there only those two equations?? the vertical and oblique ashymptopes? or are there more?

29. jim_thompson5910

nope that's it

30. iheartfood

okay and vertical is x=-4 and oblique is y=3x-12 right?

31. jim_thompson5910

correct

32. iheartfood

yay! thanks :)

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