determine...

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|dw:1352440875600:dw|
***Please show work! :) thanks :)
vertical asymptote: set the denominator equal to zero and solve for x

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Other answers:

so x=-4 ?
yes, that's the vertical asymptote
so how do i write it out?? VERTICAL ASYMPTOTE: x+4=0 -4 -4 x=-4 thats the equation of the VERTICAL asymptote?
now long divide 3x^2 - 12 into x - 4
is that how i write it out with the work?
yes
okay, so are there any oblique, horizontal or etc. asypmtotes?
the degrees of the numerator and denominator are different (and the numerator degree is larger), so we have an oblique asymptote
kk how do i find that?
long divide 3x^2 - 12 into x-4
|dw:1352441492481:dw|
|dw:1352441542380:dw| is that right??
good only focus on the quotient
so the oblique asymptote is y = 3x+12
oh so i just show the work i got above (disregarding the remainder) and my answer is y=3x+12 ?
yep
oh wait, why is it divided by x-4?
and not x+4?
hmm i for some reason thought it was x-4, my bad
so its x+4 ?
yeah sry
okay so i get this?|dw:1352442040613:dw|
so my answer is y=3x-12?
you got it
yayy!! and are there only those two equations?? the vertical and oblique ashymptopes? or are there more?
nope that's it
okay and vertical is x=-4 and oblique is y=3x-12 right?
correct
yay! thanks :)

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