multiply the numerator and denominator of the left handside by sqrt(1=x^2) =$\frac{ \sqrt{1-x ^{2}} }{ 2 }\times \frac{ \sqrt{1-x ^{2}} }{ \sqrt{1-x ^{2}} }-\frac{ (x ^{2}-x )}{ 2\sqrt{1-x ^{2}} }$=0 we get =$\frac{ (1-x ^{2})-(x ^{2}-x) }{ 2\sqrt{1-x ^{2}} }$=0 we get $-2x ^{2}+x+1=0$ is x=-1/2,1 ? yes or no?