A community for students.
Here's the question you clicked on:
 0 viewing
gerryliyana
 2 years ago
Determine whether y(x) = (2e^x) + (xe^x) is a solution of y'' + 2y' + y = 0
gerryliyana
 2 years ago
Determine whether y(x) = (2e^x) + (xe^x) is a solution of y'' + 2y' + y = 0

This Question is Closed

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.1\[y= 2e^{x} + xe^{x}\] \[y'=\] \[y''=\]

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.1find the first and second derivatives , if \(y\) is a solution then \[y'' + 2y' + y = 0\]

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.1what do you get for the first and second derivative?

gerryliyana
 2 years ago
Best ResponseYou've already chosen the best response.0yes of course.., y' (x) = 2e^(x) + e^(x)  xe^(x) = e^(x)  xe^(x) right??

gerryliyana
 2 years ago
Best ResponseYou've already chosen the best response.0ok for y'' (x) = e^(x)  e^(x) + xe^(x) = ex^x

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.1thats right but i think you typed the very last bit the wrong way around. now substitute these into \[y′′+2y′+y=0\] \[ (xe^{−x})+2(−e^{−x}−xe^{−x})+(2e−x+xe^{−x})=0\] if y is a solution then this will simplify to a statement that is always true
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.