. a bus travel at 36 km/h and arrives in its destination half an hour late. If it travels at 42 km/h, it arrives at the same destination half an hour earlier. Find the journey distance.

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. a bus travel at 36 km/h and arrives in its destination half an hour late. If it travels at 42 km/h, it arrives at the same destination half an hour earlier. Find the journey distance.

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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@mr.tobby Both the cases the distance is the same, Let time taken usually be t hours First case the bus arrives half an hour late. So time taken by it (t+0.5) hours Second case the bus arrives half an hour early. Time taken (t-0.5) hours Distance covered in first case \[D=36(t+0.5)\] Distance covered in second case \[D=42(t-0.5)\] Equate both these \[36(t+0.5)=42(t-0.5)\] Can you find t from this ? @mr.tobby
t=6.5 ? then?
yes, now find distance using any of the two equations.

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use D=42(t-0.5) and D = 42(t+0.5)
Check your second equation :)
wrong typed,:)
Use any of the two both will give you the same answer :)

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