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mr.tobby

  • 3 years ago

. a bus travel at 36 km/h and arrives in its destination half an hour late. If it travels at 42 km/h, it arrives at the same destination half an hour earlier. Find the journey distance.

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  1. ash2326
    • 3 years ago
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    @mr.tobby Both the cases the distance is the same, Let time taken usually be t hours First case the bus arrives half an hour late. So time taken by it (t+0.5) hours Second case the bus arrives half an hour early. Time taken (t-0.5) hours Distance covered in first case \[D=36(t+0.5)\] Distance covered in second case \[D=42(t-0.5)\] Equate both these \[36(t+0.5)=42(t-0.5)\] Can you find t from this ? @mr.tobby

  2. mr.tobby
    • 3 years ago
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    t=6.5 ? then?

  3. ash2326
    • 3 years ago
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    yes, now find distance using any of the two equations.

  4. mr.tobby
    • 3 years ago
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    use D=42(t-0.5) and D = 42(t+0.5)

  5. ash2326
    • 3 years ago
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    Check your second equation :)

  6. mr.tobby
    • 3 years ago
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    wrong typed,:)

  7. ash2326
    • 3 years ago
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    Use any of the two both will give you the same answer :)

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