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mr.tobby
. a bus travel at 36 km/h and arrives in its destination half an hour late. If it travels at 42 km/h, it arrives at the same destination half an hour earlier. Find the journey distance.
@mr.tobby Both the cases the distance is the same, Let time taken usually be t hours First case the bus arrives half an hour late. So time taken by it (t+0.5) hours Second case the bus arrives half an hour early. Time taken (t-0.5) hours Distance covered in first case \[D=36(t+0.5)\] Distance covered in second case \[D=42(t-0.5)\] Equate both these \[36(t+0.5)=42(t-0.5)\] Can you find t from this ? @mr.tobby
yes, now find distance using any of the two equations.
use D=42(t-0.5) and D = 42(t+0.5)
Check your second equation :)
Use any of the two both will give you the same answer :)