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ajprincessBest ResponseYou've already chosen the best response.2
This is of the form u/v. (u/v)'=(u'vv'u)/v^2 Here u=x^2 and v=(1+x)^2. (x^n)'=nx^(n1) Can u do it @emcrazy14?
 one year ago

emcrazy14Best ResponseYou've already chosen the best response.0
I got the answer 2x/(1+x)^3. Is it correct?
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
differentiate: 1/(1/x + 1)^2
 one year ago

ajprincessBest ResponseYou've already chosen the best response.2
check the sign @emcrazy14. It shud be 2x/(1+x)^3
 one year ago

emcrazy14Best ResponseYou've already chosen the best response.0
Ok, thanks. Do I multiply (x+1) with a negative sign to change it into (1+x) so that it cancels with the the denominator (1+x)^4?
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
just ask the wolf for differentiation Question.
 one year ago

emcrazy14Best ResponseYou've already chosen the best response.0
Then how oes it become +2x? :O
 one year ago

emcrazy14Best ResponseYou've already chosen the best response.0
@experimentX : wolf? :O *does
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
http://www.wolframalpha.com/input/?i=differentiate+x^2%2F%281%2Bx%29^2
 one year ago

ajprincessBest ResponseYou've already chosen the best response.2
dw:1352469822062:dwdw:1352469940166:dwdw:1352470079425:dw
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
\[ x^2/(1+x)^2 = 1/(1/x + 1)^2 = ({1 \over x} + 1)^{2}\] use chain rule ... this should be shorter.
 one year ago

emcrazy14Best ResponseYou've already chosen the best response.0
@ajprincess : Get it now. Thank you so much! :D
 one year ago

ajprincessBest ResponseYou've already chosen the best response.2
welcome:) @experimentX's method is much more simpler. U can use that too.:)
 one year ago

emcrazy14Best ResponseYou've already chosen the best response.0
@experimentX : Once I perfect this one, I'll use the one you mentioned. Thank you! :)
 one year ago
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