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ajprincess Group TitleBest ResponseYou've already chosen the best response.2
This is of the form u/v. (u/v)'=(u'vv'u)/v^2 Here u=x^2 and v=(1+x)^2. (x^n)'=nx^(n1) Can u do it @emcrazy14?
 2 years ago

emcrazy14 Group TitleBest ResponseYou've already chosen the best response.0
I got the answer 2x/(1+x)^3. Is it correct?
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
differentiate: 1/(1/x + 1)^2
 2 years ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
check the sign @emcrazy14. It shud be 2x/(1+x)^3
 2 years ago

emcrazy14 Group TitleBest ResponseYou've already chosen the best response.0
Ok, thanks. Do I multiply (x+1) with a negative sign to change it into (1+x) so that it cancels with the the denominator (1+x)^4?
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
just ask the wolf for differentiation Question.
 2 years ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
nope. (x+1)=(1+x)
 2 years ago

emcrazy14 Group TitleBest ResponseYou've already chosen the best response.0
Then how oes it become +2x? :O
 2 years ago

emcrazy14 Group TitleBest ResponseYou've already chosen the best response.0
@experimentX : wolf? :O *does
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
http://www.wolframalpha.com/input/?i=differentiate+x^2%2F%281%2Bx%29^2
 2 years ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
dw:1352469822062:dwdw:1352469940166:dwdw:1352470079425:dw
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
\[ x^2/(1+x)^2 = 1/(1/x + 1)^2 = ({1 \over x} + 1)^{2}\] use chain rule ... this should be shorter.
 2 years ago

emcrazy14 Group TitleBest ResponseYou've already chosen the best response.0
@ajprincess : Get it now. Thank you so much! :D
 2 years ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
welcome:) @experimentX's method is much more simpler. U can use that too.:)
 2 years ago

emcrazy14 Group TitleBest ResponseYou've already chosen the best response.0
@experimentX : Once I perfect this one, I'll use the one you mentioned. Thank you! :)
 2 years ago
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