Here's the question you clicked on:
emcrazy14
Differentiate; x^2/(1+x)^2
This is of the form u/v. (u/v)'=(u'v-v'u)/v^2 Here u=x^2 and v=(1+x)^2. (x^n)'=nx^(n-1) Can u do it @emcrazy14?
I got the answer -2x/(1+x)^3. Is it correct?
differentiate: 1/(1/x + 1)^2
check the sign @emcrazy14. It shud be 2x/(1+x)^3
Ok, thanks. Do I multiply (x+1) with a negative sign to change it into (1+x) so that it cancels with the the denominator (1+x)^4?
just ask the wolf for differentiation Question.
Then how oes it become +2x? :O
@experimentX : wolf? :O *does
http://www.wolframalpha.com/input/?i=differentiate+x^2%2F%281%2Bx%29^2
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\[ x^2/(1+x)^2 = 1/(1/x + 1)^2 = ({1 \over x} + 1)^{-2}\] use chain rule ... this should be shorter.
@ajprincess : Get it now. Thank you so much! :D
welcome:) @experimentX's method is much more simpler. U can use that too.:)
@experimentX : Once I perfect this one, I'll use the one you mentioned. Thank you! :)