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HighlyEducated87

  • 3 years ago

Find the constant k so that the quadratic equation 2x^2 + 5x - k = 0 has two real solutions?

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  1. terenzreignz
    • 3 years ago
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    Quadratic Formula!!! :D

  2. aroub
    • 3 years ago
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    First you find the delta: b^2-4ac 5^2-4(2)(-k) 25+8k because it has two real solutions..so, 25+8k>0 8k>-25 k>-25/8

  3. HighlyEducated87
    • 3 years ago
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    Good Job u got it 1st!!!!!

  4. terenzreignz
    • 3 years ago
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    \[\frac{-b \pm \sqrt{b^{2}-4ac}}{2a}\] Yeah, as per @aroub delta (I thought it was discriminant) determines the number of roots you have, as well as their nature... Delta is that expression in the radical in the quadratic formula :D

  5. HighlyEducated87
    • 3 years ago
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    It is discriminant but i didn't need a quadratic formula.

  6. aroub
    • 3 years ago
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    When you want to find K, no need!

  7. HighlyEducated87
    • 3 years ago
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    i know!!! Thanks

  8. aroub
    • 3 years ago
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    No problem!!

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