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HighlyEducated87 Group Title

Find the constant k so that the quadratic equation 2x^2 + 5x - k = 0 has two real solutions?

  • one year ago
  • one year ago

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  1. terenzreignz Group Title
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    Quadratic Formula!!! :D

    • one year ago
  2. aroub Group Title
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    First you find the delta: b^2-4ac 5^2-4(2)(-k) 25+8k because it has two real solutions..so, 25+8k>0 8k>-25 k>-25/8

    • one year ago
  3. HighlyEducated87 Group Title
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    Good Job u got it 1st!!!!!

    • one year ago
  4. terenzreignz Group Title
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    \[\frac{-b \pm \sqrt{b^{2}-4ac}}{2a}\] Yeah, as per @aroub delta (I thought it was discriminant) determines the number of roots you have, as well as their nature... Delta is that expression in the radical in the quadratic formula :D

    • one year ago
  5. HighlyEducated87 Group Title
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    It is discriminant but i didn't need a quadratic formula.

    • one year ago
  6. aroub Group Title
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    When you want to find K, no need!

    • one year ago
  7. HighlyEducated87 Group Title
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    i know!!! Thanks

    • one year ago
  8. aroub Group Title
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    No problem!!

    • one year ago
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