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HighlyEducated87
Find the constant k so that the quadratic equation 2x^2 + 5x - k = 0 has two real solutions?
Quadratic Formula!!! :D
First you find the delta: b^2-4ac 5^2-4(2)(-k) 25+8k because it has two real solutions..so, 25+8k>0 8k>-25 k>-25/8
Good Job u got it 1st!!!!!
\[\frac{-b \pm \sqrt{b^{2}-4ac}}{2a}\] Yeah, as per @aroub delta (I thought it was discriminant) determines the number of roots you have, as well as their nature... Delta is that expression in the radical in the quadratic formula :D
It is discriminant but i didn't need a quadratic formula.
When you want to find K, no need!
i know!!! Thanks