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psk981

  • 3 years ago

find the inverse laplace transform of (36s^4+12s^2+1)/s^6

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  1. psk981
    • 3 years ago
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    \[\frac{ 36s ^{4}+12s^{2}+1 }{ s^6}\]

  2. experimentX
    • 3 years ago
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    36/s^3 + 12/s^4 + 1/s^6 do it individually.

  3. experimentX
    • 3 years ago
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    http://www.wolframalpha.com/input/?i=inverse+laplace+transform+1%2Fs^n \( \Gamma(n) = (n-1)! \)

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