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mayankdevnani

  • 2 years ago

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  1. mayankdevnani
    • 2 years ago
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    A body of mass 6 kg is under a force of 6 N which causes displacement in it given by \[S=\frac{t^2}{4}m\].The work done by the force in 2 s is-

  2. mayankdevnani
    • 2 years ago
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    @amistre64 @ParthKohli @ajprincess @aroub @UnkleRhaukus @experimentX @ganeshie8 @gerryliyana @CliffSedge @mahmit2012

  3. CliffSedge
    • 2 years ago
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    Work = force × distance. Plug in your t=2s to solve for s, then multiply.

  4. mayankdevnani
    • 2 years ago
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    w=6*s

  5. mayankdevnani
    • 2 years ago
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    @phi have a look

  6. mayankdevnani
    • 2 years ago
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    \[S=\frac{2^2}{4}=1\]

  7. mayankdevnani
    • 2 years ago
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    right @ajprincess and @phi

  8. ajprincess
    • 2 years ago
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    yup perfect:)

  9. phi
    • 2 years ago
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    yes. s is 1 meter force is 6 N work is 6 N-m

  10. mayankdevnani
    • 2 years ago
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    sure @phi

  11. phi
    • 2 years ago
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    of course N-m is a joule so 6 joules

  12. mayankdevnani
    • 2 years ago
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    @phi

  13. phi
    • 2 years ago
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    Q14 does not say the force is 6 N.

  14. mayankdevnani
    • 2 years ago
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    it says 3J but you say 6J

  15. phi
    • 2 years ago
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    the question says "6 kg under a force that causes a displacement..." we need to find F, using F= ma we need a use d = 1/2 a t^2 we know d and t so we find a, then F and finally W = F d

  16. mayankdevnani
    • 2 years ago
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    @Aperogalics

  17. phi
    • 2 years ago
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    d (or s) in this case is 1 m t is 2 sec 1 = 1/2 a 2^2 a= 1/2 m/s^2 F= ma = 6*1/2 = 3 N W = F d = 3N * 1m = 3 N-m = 3 J

  18. mayankdevnani
    • 2 years ago
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    so my question is also same @phi

  19. phi
    • 2 years ago
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    your question says: mass 6 kg is under a force of 6 N ... you gave the force as 6 N so that is what I would use....

  20. mayankdevnani
    • 2 years ago
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    what do you mean? @phi

  21. phi
    • 2 years ago
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    Q14 requires that you find the force... Your 1st question may be inconsistent? i.e. 6 kg and 6 N don't mesh with the displacement?

  22. mayankdevnani
    • 2 years ago
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    oh!!

  23. mayankdevnani
    • 2 years ago
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    thnx..... @phi

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