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mayankdevnani Group Title

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  • 2 years ago
  • 2 years ago

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  1. mayankdevnani Group Title
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    A body of mass 6 kg is under a force of 6 N which causes displacement in it given by \[S=\frac{t^2}{4}m\].The work done by the force in 2 s is-

    • 2 years ago
  2. mayankdevnani Group Title
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    @amistre64 @ParthKohli @ajprincess @aroub @UnkleRhaukus @experimentX @ganeshie8 @gerryliyana @CliffSedge @mahmit2012

    • 2 years ago
  3. CliffSedge Group Title
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    Work = force × distance. Plug in your t=2s to solve for s, then multiply.

    • 2 years ago
  4. mayankdevnani Group Title
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    w=6*s

    • 2 years ago
  5. mayankdevnani Group Title
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    @phi have a look

    • 2 years ago
  6. mayankdevnani Group Title
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    \[S=\frac{2^2}{4}=1\]

    • 2 years ago
  7. mayankdevnani Group Title
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    right @ajprincess and @phi

    • 2 years ago
  8. ajprincess Group Title
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    yup perfect:)

    • 2 years ago
  9. phi Group Title
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    yes. s is 1 meter force is 6 N work is 6 N-m

    • 2 years ago
  10. mayankdevnani Group Title
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    sure @phi

    • 2 years ago
  11. phi Group Title
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    of course N-m is a joule so 6 joules

    • 2 years ago
  12. mayankdevnani Group Title
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    @phi

    • 2 years ago
  13. phi Group Title
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    Q14 does not say the force is 6 N.

    • 2 years ago
  14. mayankdevnani Group Title
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    it says 3J but you say 6J

    • 2 years ago
  15. phi Group Title
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    the question says "6 kg under a force that causes a displacement..." we need to find F, using F= ma we need a use d = 1/2 a t^2 we know d and t so we find a, then F and finally W = F d

    • 2 years ago
  16. mayankdevnani Group Title
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    @Aperogalics

    • 2 years ago
  17. phi Group Title
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    d (or s) in this case is 1 m t is 2 sec 1 = 1/2 a 2^2 a= 1/2 m/s^2 F= ma = 6*1/2 = 3 N W = F d = 3N * 1m = 3 N-m = 3 J

    • 2 years ago
  18. mayankdevnani Group Title
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    so my question is also same @phi

    • 2 years ago
  19. phi Group Title
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    your question says: mass 6 kg is under a force of 6 N ... you gave the force as 6 N so that is what I would use....

    • 2 years ago
  20. mayankdevnani Group Title
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    what do you mean? @phi

    • 2 years ago
  21. phi Group Title
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    Q14 requires that you find the force... Your 1st question may be inconsistent? i.e. 6 kg and 6 N don't mesh with the displacement?

    • 2 years ago
  22. mayankdevnani Group Title
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    oh!!

    • 2 years ago
  23. mayankdevnani Group Title
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    thnx..... @phi

    • 2 years ago
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