mayankdevnani
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mayankdevnani
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A body of mass 6 kg is under a force of 6 N which causes displacement in it given by \[S=\frac{t^2}{4}m\].The work done by the force in 2 s is-
mayankdevnani
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@amistre64 @ParthKohli @ajprincess @aroub @UnkleRhaukus @experimentX @ganeshie8 @gerryliyana @CliffSedge @mahmit2012
CliffSedge
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Work = force × distance.
Plug in your t=2s to solve for s, then multiply.
mayankdevnani
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w=6*s
mayankdevnani
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@phi have a look
mayankdevnani
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\[S=\frac{2^2}{4}=1\]
mayankdevnani
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right @ajprincess and @phi
ajprincess
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yup perfect:)
phi
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yes. s is 1 meter
force is 6 N
work is 6 N-m
mayankdevnani
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sure @phi
phi
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of course N-m is a joule
so
6 joules
mayankdevnani
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@phi
phi
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Q14 does not say the force is 6 N.
mayankdevnani
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it says 3J but you say 6J
phi
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the question says "6 kg under a force that causes a displacement..."
we need to find F, using F= ma
we need a
use d = 1/2 a t^2
we know d and t so we find a, then F and finally W = F d
mayankdevnani
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@Aperogalics
phi
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d (or s) in this case is 1 m
t is 2 sec
1 = 1/2 a 2^2
a= 1/2 m/s^2
F= ma = 6*1/2 = 3 N
W = F d = 3N * 1m = 3 N-m = 3 J
mayankdevnani
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so my question is also same @phi
phi
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your question says: mass 6 kg is under a force of 6 N ...
you gave the force as 6 N so that is what I would use....
mayankdevnani
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what do you mean? @phi
phi
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Q14 requires that you find the force...
Your 1st question may be inconsistent? i.e. 6 kg and 6 N don't mesh with the displacement?
mayankdevnani
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oh!!
mayankdevnani
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thnx..... @phi