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babystar16
Group Title
phil has 50 nickles and dimes worth $4.15. how many dimes does he have?
 one year ago
 one year ago
babystar16 Group Title
phil has 50 nickles and dimes worth $4.15. how many dimes does he have?
 one year ago
 one year ago

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satellite73 Group TitleBest ResponseYou've already chosen the best response.0
\(10x+5(50x)=415\) if the number of dimes is \(x\)
 one year ago

robert2 Group TitleBest ResponseYou've already chosen the best response.1
Your Answer: Laura. . . it looks like the answer of "daSVgrouch" is incorrect. Here is the correct answer for you: Let n = number of nickels Let d = number of dimes The total of our individual nickels and dimes, is 50. So: n + d = 50 Also, we know that our total in money is 415 cents. 5n + 10d = 415 So, we have 2 equations. n + d = 50 (equation 1) 5n + 10d = 415 (equation 2) We can use addition, subtraction, or substitution. 5n + 5d = 250 (equation 1 multiplied through by "negative 5") 5n + 10d = 415 Now add the two equations. . . 0n + 5d = 165 Simplify. . . 5d = 165 d = 33 If d = 33 and we have 50 total coins, then n = 17. He has 33 dimes. Source(s): I used to teach mathematics in high school.
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
dimes are worth ten cents each, and if there are a total of 50 coins and \(x\) dimes then there are \(50x\) nickles worth 5 cents each. you have a total of 415 cents so set \[10x+5(50x)=415\]solve for \(x\)
 one year ago

babystar16 Group TitleBest ResponseYou've already chosen the best response.0
thank u again im in geomerty and math models in high school right now and i need help badly
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
can you solve this equation? or do you still need help with it?
 one year ago
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