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mskyeg

Find the roots of the polynomial equation. 2x^3 + 2x^2 – 19x + 20 = 0

  • one year ago
  • one year ago

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  1. mskyeg
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    • one year ago
  2. RadEn
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    2x^3 + 2x^2 – 19x + 20 = 0, it can be factored (x+4)(2x^2-6x+5) = 0 for zeros, x+4=0 ---> x=-4 2x^2-6x+5=0 use the formula quadratic : x1,2 = (-b+-sqrt(b^2-4ac))/2a x1,2 = (6+-sqrt(36-4*2*5))/2*2 x1,2 = (6+-sqrt(36-40))/4 x1,2 = (6+-sqrt(-4))/4 x1,2 = (6+-2i)/4 x1,2 = 6/4 +- i/2 x1,2 = 3/2 +- i/2

    • one year ago
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