jbarber
PLZ HELP......you can verify the zeros of the function y=x^2+6x-7 by using a graph and finding where the graph
A. is at a minimum
B. is at a max
C. crosses the x-axis
D. crosses the y-axis
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CalebBeavers
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The zeros of a function is where it crosses the x axis
ksaimouli
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it is c
jbarber
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thank u
ksaimouli
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:-)
jbarber
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mind helping me again pl
ksaimouli
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ok
jbarber
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find the vertex of the parabola by completing the square x^2-6x+8=y
ksaimouli
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do u need the answer or explanation
ksaimouli
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◊ Group ◊
y = (x² - 6x) + 8
◊ Complete the square ◊
y = (x² - 6x + 9) + 8 - 9
◊ Write as a binomial squared ◊
y = (x-3)² - 1
jbarber
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both plz
jbarber
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the choose are
A.(-3,-6)
b(3,-1)
C(-3,1)
D(-1,3)