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3, 12, 21, 30, 39.... What is the arithmetic function of this sequence?
I know we add 9 to it each time but I need to figure out the function. Kind of stuck...
 one year ago
 one year ago
3, 12, 21, 30, 39.... What is the arithmetic function of this sequence? I know we add 9 to it each time but I need to figure out the function. Kind of stuck...
 one year ago
 one year ago

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AccessDeniedBest ResponseYou've already chosen the best response.1
What are your input values of your function, and what are your output values?
 one year ago

rachelk09Best ResponseYou've already chosen the best response.0
I don't have any input values. The output values are as I indicated...3, 12, 21, 30, 39...etc.
 one year ago

phiBest ResponseYou've already chosen the best response.0
add 9 to it each time what do you do to 3 to get each number? add 9, then 2*9 , then 3*9...
 one year ago

rachelk09Best ResponseYou've already chosen the best response.0
If I do f(n) = 3+9n this would work but only if things start at n=0
 one year ago

AccessDeniedBest ResponseYou've already chosen the best response.1
For the function, if we want it to represent this sequence, it probably should return the first value as 3 ( f(1) = 3 ), the next value as 12 ( f(2) = 12 ), then 21 ( f(3) = 21 ), and so on. So, these are our 'points.' We just have to figure out the general formula. Use the fact that you add 9 a different number of times to 3 to get to all of your function's output values...
 one year ago

rachelk09Best ResponseYou've already chosen the best response.0
Doesn't the sequence start at n=1
 one year ago

AccessDeniedBest ResponseYou've already chosen the best response.1
Hm.. I think you could technically start it at either n=0 or n=1. It shouldn't matter too much, but I'm not sure if your teacher may have a preference that he/she used?
 one year ago

rachelk09Best ResponseYou've already chosen the best response.0
She really didn't say...hmm..I guess I'll just try it and indicate that n starts at 0
 one year ago

AccessDeniedBest ResponseYou've already chosen the best response.1
K. If you wanted to move it to n=1 => f(1) = 3, you could just use a function shift: f(n) = 3 + 9n f(n1) = 3 + 9(n1) = 3 + 9n  9 = 6 + 9n < call this the new f(n)
 one year ago

AccessDeniedBest ResponseYou've already chosen the best response.1
I think I would prefer the start at n=0, just because it is easier to see your first term. :)
 one year ago
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