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jorourk3
 2 years ago
antiderivative(18)/(5x) = kln[5x]+c
Find the exact value of k that makes the antidifferentiation formula true.
jorourk3
 2 years ago
antiderivative(18)/(5x) = kln[5x]+c Find the exact value of k that makes the antidifferentiation formula true.

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mark_o.
 2 years ago
Best ResponseYou've already chosen the best response.1@ jorourk3 \[\int\limits_{}^{}\frac{ 18 }{ 5x }=18\ln(x5)+C\]=kln[5x]+c seems like k=1 ? yes or no?

jorourk3
 2 years ago
Best ResponseYou've already chosen the best response.0k would be 18 then by what your saying...wouldnt it? that is also absolute value signs around ln[x5] btw...does that change it from what you are saying?

jorourk3
 2 years ago
Best ResponseYou've already chosen the best response.0its correct! thanks! i dont understand why it is negative though?

mark_o.
 2 years ago
Best ResponseYou've already chosen the best response.1its negative bec you let u=5x then du= dx

jorourk3
 2 years ago
Best ResponseYou've already chosen the best response.0ok thanks....can you help me with a similar one please? :)

mark_o.
 2 years ago
Best ResponseYou've already chosen the best response.1ok yw ..:D just post them again so that others can see them
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