## anonymous 4 years ago antiderivative(18)/(5-x) = kln[5-x]+c Find the exact value of k that makes the antidifferentiation formula true.

1. anonymous

i got 18 but is wrong

2. anonymous

@ jorourk3 $\int\limits_{}^{}\frac{ 18 }{ 5-x }=-18\ln(x-5)+C$=kln[5-x]+c seems like k=-1 ? yes or no?

3. anonymous

im sorry its -18 :D

4. anonymous

k would be -18 then by what your saying...wouldnt it? that is also absolute value signs around ln[x-5] btw...does that change it from what you are saying?

5. anonymous

its correct! thanks! i dont understand why it is negative though?

6. anonymous

its negative bec you let u=5-x then du= -dx

7. anonymous

or du/dx=-1

8. anonymous

ok thanks....can you help me with a similar one please? :)

9. anonymous

ok yw ..:D just post them again so that others can see them