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antiderivative of (11x+17)^2 = k(11x+17)^3 + C
Find the exact value of k that makes the antidifferentiation formula true.
 one year ago
 one year ago
antiderivative of (11x+17)^2 = k(11x+17)^3 + C Find the exact value of k that makes the antidifferentiation formula true.
 one year ago
 one year ago

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mark_o.Best ResponseYou've already chosen the best response.0
ok , try integrating them, then and set them equal to the right hand side let see what happen
 one year ago

jorourk3Best ResponseYou've already chosen the best response.0
what do you mean by integrating them?
 one year ago

jorourk3Best ResponseYou've already chosen the best response.0
im sorry but i dont understand what you are talking about...we just learned this stuff today and i never really got the du dx references...i just solve differentation by using the rules we are given ive been solving these equations (solve for k) but finding the antiderivative of the left side and whatever constant i got i plugged into k on the right .....but for this problem the constant i get is 11/3 which does not give you the left side when plugged into k and differentiated
 one year ago

mark_o.Best ResponseYou've already chosen the best response.0
let me know if you have question
 one year ago

jorourk3Best ResponseYou've already chosen the best response.0
it says 22/3 is wrong
 one year ago

mark_o.Best ResponseYou've already chosen the best response.0
integral (11x+17)^2 dx \[\int\limits_{}^{}(11x+17)^{2}dx\] let u=(11x+17) and du= 11 dx so that \[\int\limits_{}^{}u ^{2}du= \frac{ u ^{3} }{ 3 }+C\] since we can sub u and du we have \[\frac{ 1 }{ 11 } \int\limits_{}^{}(11x+17)^{2}[11dx]\] note dy=11dx and 1/11 is to balanced it from the original problem therefore we have \[\frac{ 1 }{ 11 }\int\limits_{}^{}u ^{2}du=\frac{ 1 }{ 11 }\frac{ u ^{3} }{ 3 }+C\] \[=\frac{ 1 }{ 33 }u ^{3}+C\] now sub u=(11x+17) we get \[=\frac{ 1 }{ 33 }(11x+17)^{3}+C=K(11x+17)^{3}+c\] can you notice K=____?
 one year ago

mark_o.Best ResponseYou've already chosen the best response.0
im sorry, on note , that was du instead of dy. therefore dU=11dx and 1/11 is to balanced it from the original problem
 one year ago

mark_o.Best ResponseYou've already chosen the best response.0
@ jorourk3 let me know if you have question,.... :D
 one year ago
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