anonymous
  • anonymous
Anyone know how to do this problem? The marginal cost of producing the xth box of light bulbs is 3 + x^2/1,000 dollars. Determine how much is added to the total cost by a change in production from x = 40 to x = 100 boxes.
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
How is marginal cost related to total cost?
anonymous
  • anonymous
@laylam25 Look back how I solved your recent post!
anonymous
  • anonymous
i didnt see whatchloropyl have done do you have the link? any way is this correct 3 + (x^2/1,000) or maybe this is (3 + x^2)/1,000

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anonymous
  • anonymous
@ laylam25
anonymous
  • anonymous
oh this is similar to that?!
anonymous
  • anonymous
its actually just written just like this: 3 + x^2/1,000
anonymous
  • anonymous
This is actually under the chapter of the "definite integral: fundamental theorem of calculus" so I am guessing I have to incorporate that somewhere :/
anonymous
  • anonymous
Total Cost is Integral of Marginal Cost! => Integrate from 40 to 100
anonymous
  • anonymous
The difference between 40 and 100 boxes is the added cost!
anonymous
  • anonymous
total cost = integral of marginal cost marginal cost = integral (3 + x^2/1,000) ? can you start this ? what did you get?
anonymous
  • anonymous
that is integral from 40 to 100
anonymous
  • anonymous
\[\int\limits_{49}^{100}(3+\frac{ x ^{2} }{ 1000 })dx=?\]
anonymous
  • anonymous
i assumed thats the correct function
anonymous
  • anonymous
is it [3x+ x^3/3(1000)] from 40 to 100 =?
anonymous
  • anonymous
is it [300 + (100)^3/3000]-[12+ (40)^3/3000] =?

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