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laylam25 Group Title

Anyone know how to do this problem? The marginal cost of producing the xth box of light bulbs is 3 + x^2/1,000 dollars. Determine how much is added to the total cost by a change in production from x = 40 to x = 100 boxes.

  • one year ago
  • one year ago

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  1. p505 Group Title
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    How is marginal cost related to total cost?

    • one year ago
  2. Chlorophyll Group Title
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    @laylam25 Look back how I solved your recent post!

    • one year ago
  3. mark_o. Group Title
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    i didnt see whatchloropyl have done do you have the link? any way is this correct 3 + (x^2/1,000) or maybe this is (3 + x^2)/1,000

    • one year ago
  4. mark_o. Group Title
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    @ laylam25

    • one year ago
  5. laylam25 Group Title
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    oh this is similar to that?!

    • one year ago
  6. laylam25 Group Title
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    its actually just written just like this: 3 + x^2/1,000

    • one year ago
  7. laylam25 Group Title
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    This is actually under the chapter of the "definite integral: fundamental theorem of calculus" so I am guessing I have to incorporate that somewhere :/

    • one year ago
  8. Chlorophyll Group Title
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    Total Cost is Integral of Marginal Cost! => Integrate from 40 to 100

    • one year ago
  9. Chlorophyll Group Title
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    The difference between 40 and 100 boxes is the added cost!

    • one year ago
  10. mark_o. Group Title
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    total cost = integral of marginal cost marginal cost = integral (3 + x^2/1,000) ? can you start this ? what did you get?

    • one year ago
  11. mark_o. Group Title
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    that is integral from 40 to 100

    • one year ago
  12. mark_o. Group Title
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    \[\int\limits_{49}^{100}(3+\frac{ x ^{2} }{ 1000 })dx=?\]

    • one year ago
  13. mark_o. Group Title
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    i assumed thats the correct function

    • one year ago
  14. mark_o. Group Title
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    is it [3x+ x^3/3(1000)] from 40 to 100 =?

    • one year ago
  15. mark_o. Group Title
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    is it [300 + (100)^3/3000]-[12+ (40)^3/3000] =?

    • one year ago
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