anonymous
  • anonymous
A ball is kicked upward with an initial velocity of 56 feet per second. The ball's height h (in feet) can be expressed as a function of time t (in seconds) by the equation h = -16t2 + 56t. How much time does the ball take to reach its highest point?
Mathematics
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anonymous
  • anonymous
A ball is kicked upward with an initial velocity of 56 feet per second. The ball's height h (in feet) can be expressed as a function of time t (in seconds) by the equation h = -16t2 + 56t. How much time does the ball take to reach its highest point?
Mathematics
katieb
  • katieb
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
@ mell6 are in calculus class? to get to the max height, differentiate h, that will be you velocity, v=dh/dt now set this to zero, dh/dt=0, then solve for t, then sub this t to h, that is the max h
anonymous
  • anonymous
are u in calculus class?
anonymous
  • anonymous
no but i got it it's like 1.25 i think

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anonymous
  • anonymous
t =1.75 sec sub this to h to get hmm max h= 49 ft? yes or no?
anonymous
  • anonymous
so you are not in calculus class? h = -16t^2 + 56t. we noticed that this is in the family of parabola y=ax^2 +b or y=-16x^2 +56x plot this on the graph the parabola is opening downward and the vertex is V=-b/2a we get V=-56/2(-16)=1.75 =x=t in sec now sub this to h = -16t2 + 56t we get max h=---?
anonymous
  • anonymous
@ mell65 let me know if you have question

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