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tkhunny
 2 years ago
Best ResponseYou've already chosen the best response.0Have you considered the 1st Derivative?

lovekblue
 2 years ago
Best ResponseYou've already chosen the best response.0i know the answer is 3..but dont know why

seitys
 2 years ago
Best ResponseYou've already chosen the best response.0criticals are where the first derivative is 0 or does not exist within a given domain. I recognize this problem from the stewart textbook hah

tkhunny
 2 years ago
Best ResponseYou've already chosen the best response.0Well then, what do you get for the 1st Derivative?

mark_o.
 2 years ago
Best ResponseYou've already chosen the best response.0if y=x^(4/5) (x4)^2 what is dy/dx ? then set up dy/dx=0 solve for x=? thats your critical poits

robtobey
 2 years ago
Best ResponseYou've already chosen the best response.0A plot is attached. The red curve is the derivative of the blue.
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