Here's the question you clicked on:
orbie
Problem attached below.
if you look at all your answers...one sticks out of them. perhaps this will help \[log(a+b)=log(a)+log(b)\] \[log(-a+b)=log(b-a)=\frac{log(b)}{log(a)}\]
The only solutions to the system are: \[ \log(a+b)=\log(a)+\log(b)\implies\\ b=\frac{a}{a-1}, a\ne0, a-1\ne0 \]
@Outkast3r09 \( \log(a+b)=\log(a)+\log(b) \) Is *not* true for all cases.
I understand the equations but I still can't find the right answers.
The first and last are the only two.
mmm...that is not right either according to my math hw program. This problem is such a hassle.
Oh, I forgot to say that \(x>0\). The last two and the first are counter-examples to these.
No, wait, never mind, it's only the first and the last.
Because that restriction doesn't hold. I don't really know... you can check them all by hand, I guess, but I'm pretty sure it's only the first and last.
Thank you! It was the first and the last two that worked.
Haha, yeah, I know why, now: the last one is imaginary, it *holds* but not in the real numbers.