Here's the question you clicked on:
echo94
If two resistors with resistances R1 and R2 are connected in parallel, as in the figure below, then the total resistance R, measured in ohms (Ω), is given by 1/R = 1/R1 + 1/R2 If R1 and R2 are increasing at rates of 0.3 Ω/s and 0.2 Ω/s, respectively, how fast is R changing when R1 = 80 Ω and R2 = 100 Ω?
It's going to be the same method as previously show, please try it, yourself.
@echo94 Utilizing @LolWolf 's solution as your guideline and feel free to ask :)