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jiteshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.2
@aceace post the question :)
 one year ago

aceace Group TitleBest ResponseYou've already chosen the best response.0
Represent the solutions sets of the following equation on a number line...\[\left x+3 \right > 1\] and \[\left 2x + 5 \right < 3\]
 one year ago

jiteshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.2
a = a if a<0 a = a if a>0 so solve (x+3)>1 & (x+3)>1 (2x+5)<3 & (2x+5)<3
 one year ago

jiteshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.2
Do u gt it @aceace ??
 one year ago

aceace Group TitleBest ResponseYou've already chosen the best response.0
yes but i got x>2 , x<4 and x<1 , x>4 but the answers are different
 one year ago

aceace Group TitleBest ResponseYou've already chosen the best response.0
Could you do it step by step for me?
 one year ago

nubeer Group TitleBest ResponseYou've already chosen the best response.0
hmm.. so what are the answers? @aceace
 one year ago

aceace Group TitleBest ResponseYou've already chosen the best response.0
they are 2<x<1
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
these are absolutely, what u got x>2 , x<4 and x<1 , x>4
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
now 'AND' means the common region between them what is common from x>2 , x<4 and x<1 , x>4 ?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
x>2 , x<4 dw:1352542195310:dw
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
x<1 , x>4 dw:1352542254504:dw so whats the common region ?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
dw:1352542362156:dw
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
ask if there are still any doubts anywhere @aceace
 one year ago

aceace Group TitleBest ResponseYou've already chosen the best response.0
i fully understand now... thanks
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
welcome ^_^
 one year ago
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