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A body of mass 2 kg is thrown up vertically with a kinetic energy of 490 J.If the acceleration due to gravity is 9.8 m/s^2, the height at which the kinetic energy of the body becomes half of the original value is - a) 50 m b) 25 m c) 12.5 m d) 10 m

Physics
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@mathslover have a look:)
First find the original value ... what you get?

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Other answers:

original value????
sorry i think it is given
Potential energy of the body =mgh
u know it?
ok!!
yaa
490 J = KE (ORIGINAL)
yaa
half of it will be 490 /2 J = 245 J , correct?
why you do the half the K.E @mathslover
@mayankdevnani because we have to find the height when the new kinetic energy equals half of the original one. ...
therefore the new kinetic energy must be equal to 245 Joules.
yaa
correct!!!
therefore we have : 1/2 m v^2 = 245 J 1/2 m (u^2 + 2gh ) = 245 J 1/2 m (2gh) = 245 mgh = 245 J 2 kg * 9.8 * h = 245
solve for h and you will get h = 12.5 m
1/2 m (u^2 + 2gh ) = 245 J ??????????????
got it?
no!!!!
1/2 m (u^2 + 2gh ) = 245 J this line!!!
since v^2 = u^2 + 2gh therefore..
ok
thnx.... i got it @mathslover
good,...
let @03225186213 be answer.... plz wait
1/2 mv^2=mgh 490/2=2 (-9.8)h h= -9.8 because it is moving against gravity
@03225186213 same I thought BUT it is given in the quest. that g = 9.8 m/s^2
yaaa you are correct thnx @mathslover and @03225186213
welcome
:)

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