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ashna

  • 3 years ago

How far from the surface of the earth does the acceleration due to gravity become 4% of its value on the surface of the earth ?

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  1. ashna
    • 3 years ago
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    @sauravshakya

  2. sauravshakya
    • 3 years ago
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    g'=4/100 *g GM/ (R+h)^2 = 4/100 * (GM/R^2)

  3. sauravshakya
    • 3 years ago
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    Now, simplify it

  4. sauravshakya
    • 3 years ago
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    can u?

  5. ashna
    • 3 years ago
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    |dw:1352535255124:dw|

  6. ashna
    • 3 years ago
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    @sauravshakya ?

  7. sauravshakya
    • 3 years ago
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    g'=4/100 *g GM/ (R+h)^2 = 4/100 * (GM/R^2) 100R^2 = 4(R+h)^2 Now, I guess R=6400*1000 m is given Then find h.

  8. ashna
    • 3 years ago
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    okay , is it 3.5 ?

  9. sauravshakya
    • 3 years ago
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    I am getting 25600 km

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