ashna
How far from the surface of the earth does the acceleration due to gravity become 4% of its value on the surface of the earth ?



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ashna
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@sauravshakya

sauravshakya
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g'=4/100 *g
GM/ (R+h)^2 = 4/100 * (GM/R^2)

sauravshakya
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Now, simplify it

sauravshakya
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can u?

ashna
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dw:1352535255124:dw

ashna
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@sauravshakya ?

sauravshakya
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g'=4/100 *g
GM/ (R+h)^2 = 4/100 * (GM/R^2)
100R^2 = 4(R+h)^2
Now, I guess R=6400*1000 m is given
Then find h.

ashna
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okay , is it 3.5 ?

sauravshakya
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I am getting 25600 km