Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

spndsh Group TitleBest ResponseYou've already chosen the best response.1
dw:1352550338176:dw
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.0
you last equation does not look correct
 2 years ago

spndsh Group TitleBest ResponseYou've already chosen the best response.1
dw:1352551028612:dw
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.0
I would solve for lambda using the 1st eq. plug into the 2nd equation and solve for x (or y) and finally use the last equation...
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.0
btw, they are all set = to 0, and you should show this...
 2 years ago

spndsh Group TitleBest ResponseYou've already chosen the best response.1
would that give the extreme points?
 2 years ago

spndsh Group TitleBest ResponseYou've already chosen the best response.1
dw:1352552076296:dw
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.0
I think you missed a factor of 9 on the y^2 term
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.0
but the crucial step is in solving, you should have found y=0 as a possible root
 2 years ago

spndsh Group TitleBest ResponseYou've already chosen the best response.1
dw:1352553005461:dw
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.0
no. you can do with z= y^2 4z^2 +9z9=0
 2 years ago

spndsh Group TitleBest ResponseYou've already chosen the best response.1
ok, whats the next step?
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.0
\[ 6x^2 2 \lambda x=0 > \lambda= 3x\] \[ 4y^3 2\lambda y=0 > y=0 \text{ or } 2y^23x=0 \] notice y = 0 is a possible solution \[ y^2= \frac{3}{2} x \] using y^2 = 3/2 x in \[ x^2 + y^2 1=0 > x^2 +\frac{3}{2}x 1 =0\] \[ x= \frac{1}{4}(3 ± 5) \] when we plug in for the various candidates (1,0) is the max value x= 2 is outside the region, x=1/2 is an inflection point
 2 years ago

spndsh Group TitleBest ResponseYou've already chosen the best response.1
ok, thanks so much
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.0
After looking at this a little more, we have possible solutions at x=0, y=±1 y=0, x=±1 x= 1/2, y= ± 3√/2 the value of f(x,y) at these points is (0,1) 1 (0,1) 1 (1,0) 1 (1,0) 2 (1/2, sqrt(3)/2) 13/16 (1/2, sqrt(3)/2) 13/16 so point (1,0) is a max with value 2 point(1,0) is a min with value 1 points (1/2,±sqrt(3)/2) is a local min points (0,±1) are local maximums
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.