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hba

  • 2 years ago

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  1. hba
    • 2 years ago
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    If \[z _{1}=1-i ,z_{2}=7+i\] then the modulus of \[\frac{ z _{1}-z _{2} }{ z _{1}z _{2} }\]

  2. hba
    • 2 years ago
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    looks like no one is interested in helping me :D

  3. hba
    • 2 years ago
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    @ash2326 @phi

  4. hba
    • 2 years ago
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    I tried to Solve it And got the final expression as \[\frac{ -6-2i }{ 8-6i }\] Do I apply the modulus now ?

  5. ash2326
    • 2 years ago
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    First find z1-z2 and z1 z2 Then take the modulus of both and divide

  6. hba
    • 2 years ago
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    @ash2326 I think you did not see my comment

  7. hba
    • 2 years ago
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    I moreover simplified it to \[-3-i/4-3i\]

  8. ash2326
    • 2 years ago
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    Now find modulus of -3-i and find modulus of 4-3i and divide both

  9. hba
    • 2 years ago
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    Taking a conjugate would help ?

  10. hba
    • 2 years ago
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    Well @ash2326 I tried it that way but it didn't help :(

  11. ash2326
    • 2 years ago
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    Are you getting a wrong answer?

  12. niksva
    • 2 years ago
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    multiply numerator and denominator by 4+3i it will make the problem more easier

  13. hba
    • 2 years ago
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    @ash2326 Yes

  14. hba
    • 2 years ago
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    @niksva This is what we call a conjugate and i was asking that only ?

  15. ash2326
    • 2 years ago
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    Answer is \[\frac{\sqrt {10}}{5}\] What did you get?

  16. niksva
    • 2 years ago
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    @hba i know what is meant by conjugate i m telling u to rationalize the function

  17. hba
    • 2 years ago
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    \[2\sqrt{2}/7\]

  18. hba
    • 2 years ago
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    LoL :D

  19. ash2326
    • 2 years ago
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    You made a mistake here. Let me show \[-3-i/4-3i\] \[|-3-i|=\sqrt{(-3)^2+(-1)^2}=\sqrt{10}\] \[|4-3i|=\sqrt{(4)^2+(-3)^2}=\sqrt {25}=5\] so you'd get \[\frac{\sqrt{10}}{5}\]

  20. hba
    • 2 years ago
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    Thanks A Lot @ash2326

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