hba
  • hba
Question...
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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hba
  • hba
If \[z _{1}=1-i ,z_{2}=7+i\] then the modulus of \[\frac{ z _{1}-z _{2} }{ z _{1}z _{2} }\]
hba
  • hba
looks like no one is interested in helping me :D
hba
  • hba
@ash2326 @phi

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More answers

hba
  • hba
I tried to Solve it And got the final expression as \[\frac{ -6-2i }{ 8-6i }\] Do I apply the modulus now ?
ash2326
  • ash2326
First find z1-z2 and z1 z2 Then take the modulus of both and divide
hba
  • hba
@ash2326 I think you did not see my comment
hba
  • hba
I moreover simplified it to \[-3-i/4-3i\]
ash2326
  • ash2326
Now find modulus of -3-i and find modulus of 4-3i and divide both
hba
  • hba
Taking a conjugate would help ?
hba
  • hba
Well @ash2326 I tried it that way but it didn't help :(
ash2326
  • ash2326
Are you getting a wrong answer?
anonymous
  • anonymous
multiply numerator and denominator by 4+3i it will make the problem more easier
hba
  • hba
@ash2326 Yes
hba
  • hba
@niksva This is what we call a conjugate and i was asking that only ?
ash2326
  • ash2326
Answer is \[\frac{\sqrt {10}}{5}\] What did you get?
anonymous
  • anonymous
@hba i know what is meant by conjugate i m telling u to rationalize the function
hba
  • hba
\[2\sqrt{2}/7\]
hba
  • hba
LoL :D
ash2326
  • ash2326
You made a mistake here. Let me show \[-3-i/4-3i\] \[|-3-i|=\sqrt{(-3)^2+(-1)^2}=\sqrt{10}\] \[|4-3i|=\sqrt{(4)^2+(-3)^2}=\sqrt {25}=5\] so you'd get \[\frac{\sqrt{10}}{5}\]
hba
  • hba
Thanks A Lot @ash2326

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