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hba
 3 years ago
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hba
 3 years ago
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hba
 3 years ago
Best ResponseYou've already chosen the best response.0If \[z _{1}=1i ,z_{2}=7+i\] then the modulus of \[\frac{ z _{1}z _{2} }{ z _{1}z _{2} }\]

hba
 3 years ago
Best ResponseYou've already chosen the best response.0looks like no one is interested in helping me :D

hba
 3 years ago
Best ResponseYou've already chosen the best response.0I tried to Solve it And got the final expression as \[\frac{ 62i }{ 86i }\] Do I apply the modulus now ?

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.1First find z1z2 and z1 z2 Then take the modulus of both and divide

hba
 3 years ago
Best ResponseYou've already chosen the best response.0@ash2326 I think you did not see my comment

hba
 3 years ago
Best ResponseYou've already chosen the best response.0I moreover simplified it to \[3i/43i\]

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.1Now find modulus of 3i and find modulus of 43i and divide both

hba
 3 years ago
Best ResponseYou've already chosen the best response.0Taking a conjugate would help ?

hba
 3 years ago
Best ResponseYou've already chosen the best response.0Well @ash2326 I tried it that way but it didn't help :(

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.1Are you getting a wrong answer?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0multiply numerator and denominator by 4+3i it will make the problem more easier

hba
 3 years ago
Best ResponseYou've already chosen the best response.0@niksva This is what we call a conjugate and i was asking that only ?

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.1Answer is \[\frac{\sqrt {10}}{5}\] What did you get?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@hba i know what is meant by conjugate i m telling u to rationalize the function

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.1You made a mistake here. Let me show \[3i/43i\] \[3i=\sqrt{(3)^2+(1)^2}=\sqrt{10}\] \[43i=\sqrt{(4)^2+(3)^2}=\sqrt {25}=5\] so you'd get \[\frac{\sqrt{10}}{5}\]
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