hba
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Question...
Mathematics
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hba
  • hba
Question...
Mathematics
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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hba
  • hba
If \[z _{1}=1-i ,z_{2}=7+i\] then the modulus of \[\frac{ z _{1}-z _{2} }{ z _{1}z _{2} }\]
hba
  • hba
looks like no one is interested in helping me :D
hba
  • hba

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hba
  • hba
I tried to Solve it And got the final expression as \[\frac{ -6-2i }{ 8-6i }\] Do I apply the modulus now ?
ash2326
  • ash2326
First find z1-z2 and z1 z2 Then take the modulus of both and divide
hba
  • hba
@ash2326 I think you did not see my comment
hba
  • hba
I moreover simplified it to \[-3-i/4-3i\]
ash2326
  • ash2326
Now find modulus of -3-i and find modulus of 4-3i and divide both
hba
  • hba
Taking a conjugate would help ?
hba
  • hba
Well @ash2326 I tried it that way but it didn't help :(
ash2326
  • ash2326
Are you getting a wrong answer?
anonymous
  • anonymous
multiply numerator and denominator by 4+3i it will make the problem more easier
hba
  • hba
hba
  • hba
@niksva This is what we call a conjugate and i was asking that only ?
ash2326
  • ash2326
Answer is \[\frac{\sqrt {10}}{5}\] What did you get?
anonymous
  • anonymous
@hba i know what is meant by conjugate i m telling u to rationalize the function
hba
  • hba
\[2\sqrt{2}/7\]
hba
  • hba
LoL :D
ash2326
  • ash2326
You made a mistake here. Let me show \[-3-i/4-3i\] \[|-3-i|=\sqrt{(-3)^2+(-1)^2}=\sqrt{10}\] \[|4-3i|=\sqrt{(4)^2+(-3)^2}=\sqrt {25}=5\] so you'd get \[\frac{\sqrt{10}}{5}\]
hba
  • hba
Thanks A Lot @ash2326

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