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What is the midpoint of (–2, 0) and (4, –2)? (0, 0) (2, –2) (1, –1) (–6, 2)

Mathematics
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What is the distance between points (12, 4) and (18, –1)? Round to the nearest tenth. 7.8 6.1 4.7 9.9
mid point x2-x1/2 y2-y1/2
does that apply to question two too?

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Other answers:

\[distance=\sqrt{(x2-x1)^2+(y2-y1)2}\]
|dw:1352553953588:dw|
(1,-1) is ans
|dw:1352554035396:dw|
|dw:1352554166824:dw|
You guys are the best thank you all. I will calculate and tell you if i got right then close. You're all lifesavers thank you!
my ans is frist question means mid point
|dw:1352554456108:dw|
this is right fig.
Thats what my teacher has for the question though and I got 1,-1
why
|dw:1352554954836:dw|
Unkle could you explain to me how to get the distance to second one with the formula I keep getting 45 am i supposed to square root it right?
distance is 7.8
\[d=\sqrt{5^2+6^2}=\sqrt{25+36}=\sqrt{61}\approx8\]
Ooh thank you okay sunny thank you too
this is true but solve |dw:1352555257628:dw|

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