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Brooke_army
 2 years ago
Best ResponseYou've already chosen the best response.0ok for this question i think im doing something wrong i got the answer of 17 but this is not right please help

nubeer
 2 years ago
Best ResponseYou've already chosen the best response.0can you find dy/dx of the given equation?

phi
 2 years ago
Best ResponseYou've already chosen the best response.1when you take the derivative wrt to t you should get a dx/dt term

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0u need to use chain rule d/dt(5x) = 5 d/dx (dx/dt)

phi
 2 years ago
Best ResponseYou've already chosen the best response.1instead of d/dx x^3 = 3 x^2 dx/dx you do d/dt x^3 = 3 x^2 dx/dt

phi
 2 years ago
Best ResponseYou've already chosen the best response.1if you think \[ \frac{d}{dx} x= 1\] think this \[ \frac{ d}{dx} x= \frac{dx}{dx}= 1\]

sunnymony
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1352559750685:dw

phi
 2 years ago
Best ResponseYou've already chosen the best response.1using the same logic \[ \frac{d }{dt} x= \frac{dx}{dt} \]

Brooke_army
 2 years ago
Best ResponseYou've already chosen the best response.0thanks so much i got the wright answer!!

sunnymony
 2 years ago
Best ResponseYou've already chosen the best response.0dy/dx= 3x2+5 dx/dt = 5 so both multiply we get =15x2+25

phi
 2 years ago
Best ResponseYou've already chosen the best response.1then you got dy/dt=3x^2 dx/dt + 5 dx/dt replace x=2, dx/dt=5 to get dy/dt = 3*4*5+ 5*5= 85

sunnymony
 2 years ago
Best ResponseYou've already chosen the best response.0so 15( 2x2)+25 =60+25 85
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