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can you find dy/dx of the given equation?

dy/dt=3x^2+5

when you take the derivative wrt to t
you should get a dx/dt term

u need to use chain rule
d/dt(5x) = 5 d/dx (dx/dt)

instead of d/dx x^3 = 3 x^2 dx/dx you do
d/dt x^3 = 3 x^2 dx/dt

if you think
\[ \frac{d}{dx} x= 1\]
think this
\[ \frac{ d}{dx} x= \frac{dx}{dx}= 1\]

|dw:1352559750685:dw|

using the same logic
\[ \frac{d }{dt} x= \frac{dx}{dt} \]

3x2+5 is ans

thanks so much i got the wright answer!!

dy/dx= 3x2+5
dx/dt = 5
so both multiply we get =15x2+25

then you got
dy/dt=3x^2 dx/dt + 5 dx/dt
replace x=2, dx/dt=5 to get
dy/dt = 3*4*5+ 5*5= 85

so 15( 2x2)+25
=60+25
85