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If y=x3+5x and dx/dt=5, find dy/dt when x=2.

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ok for this question i think im doing something wrong i got the answer of 17 but this is not right please help
can you find dy/dx of the given equation?

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Other answers:

  • phi
when you take the derivative wrt to t you should get a dx/dt term
u need to use chain rule d/dt(5x) = 5 d/dx (dx/dt)
  • phi
instead of d/dx x^3 = 3 x^2 dx/dx you do d/dt x^3 = 3 x^2 dx/dt
  • phi
if you think \[ \frac{d}{dx} x= 1\] think this \[ \frac{ d}{dx} x= \frac{dx}{dx}= 1\]
  • phi
using the same logic \[ \frac{d }{dt} x= \frac{dx}{dt} \]
3x2+5 is ans
thanks so much i got the wright answer!!
dy/dx= 3x2+5 dx/dt = 5 so both multiply we get =15x2+25
  • phi
then you got dy/dt=3x^2 dx/dt + 5 dx/dt replace x=2, dx/dt=5 to get dy/dt = 3*4*5+ 5*5= 85
so 15( 2x2)+25 =60+25 85
thats right @phi

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