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QUICK QUESTION!!** PIC INCLUDED* Suppose that a box is being towed up an inclined plane as shown in the figure. Find the force w needed to make the component of the force parallel to the inclined plane equal to 2.5 lb. Give answer in component form.
 one year ago
 one year ago
QUICK QUESTION!!** PIC INCLUDED* Suppose that a box is being towed up an inclined plane as shown in the figure. Find the force w needed to make the component of the force parallel to the inclined plane equal to 2.5 lb. Give answer in component form.
 one year ago
 one year ago

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redshiftBest ResponseYou've already chosen the best response.0
We will need that figure to know exactly what is being asked.
 one year ago

butterflyprincessBest ResponseYou've already chosen the best response.0
Here is a picture!
 one year ago

butterflyprincessBest ResponseYou've already chosen the best response.0
Does anyone know how to solve it D=
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
dw:1352583686628:dw
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
dw:1352583791078:dw
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
the component parallel to the plane is the magnitude of the force W time the cosine of the angle between the force and the plane, which is 3015=15degrees
 one year ago

butterflyprincessBest ResponseYou've already chosen the best response.0
Wait but the angle given says 33 degrees?
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
dw:1352584030549:dw
 one year ago

butterflyprincessBest ResponseYou've already chosen the best response.0
but how would you get the component form..... like what exactly do i solve for? w?
 one year ago

butterflyprincessBest ResponseYou've already chosen the best response.0
mhm, okay but how do you know what you have to minus 33 with 15?
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
we want the angle between the ramp and the force the ramp is at an angle of 15 deg to the horizontal the force is at an angle of 33 deg to the horizontal therefore the angle between the force and the ramp is 3315deg
 one year ago

butterflyprincessBest ResponseYou've already chosen the best response.0
Oh okay cool, so how can you set it up to get W?cos 18 = 2.5lbs/w..?
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
start with cos(theta)=F/W where F is the component parallel to the plane we set theta=18 and F=2.5 now yuo can solve for W
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
cuz it's a right triangle...dw:1352584629296:dw
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
cos(theta)=adj/hyp=F/W
 one year ago

butterflyprincessBest ResponseYou've already chosen the best response.0
ohh Okay so W=2.63/
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
I dunno, let me find a calculator...
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
yep, I get the same :)
 one year ago

butterflyprincessBest ResponseYou've already chosen the best response.0
oh okay but the answer says in the book <2.20,1.43> so how can i get there?
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
those must be the *components* of W, so it is W*cos(phi) W*sin(phi) where phi is the angle that W makes with the horizontal
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
dw:1352585011969:dwhere my exaggerated drawing doesn't work so well :P but Wx and Wy are the x and y components respectively
 one year ago

butterflyprincessBest ResponseYou've already chosen the best response.0
what so youd get like (2.62 cos (18) , 2.62 sin (18)?
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
18 is not the angle that W makes with the horizontal...
 one year ago

butterflyprincessBest ResponseYou've already chosen the best response.0
wait really then what would it be?O:
 one year ago
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