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butterflyprincess
 3 years ago
QUICK QUESTION!!** PIC INCLUDED* Suppose that a box is being towed up an inclined plane as shown in the figure. Find the force w needed to make the component of the force parallel to the inclined plane equal to 2.5 lb. Give answer in component form.
butterflyprincess
 3 years ago
QUICK QUESTION!!** PIC INCLUDED* Suppose that a box is being towed up an inclined plane as shown in the figure. Find the force w needed to make the component of the force parallel to the inclined plane equal to 2.5 lb. Give answer in component form.

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redshift
 3 years ago
Best ResponseYou've already chosen the best response.0We will need that figure to know exactly what is being asked.

butterflyprincess
 3 years ago
Best ResponseYou've already chosen the best response.0Here is a picture!

butterflyprincess
 3 years ago
Best ResponseYou've already chosen the best response.0Does anyone know how to solve it D=

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1352583686628:dw

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1352583791078:dw

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.1the component parallel to the plane is the magnitude of the force W time the cosine of the angle between the force and the plane, which is 3015=15degrees

butterflyprincess
 3 years ago
Best ResponseYou've already chosen the best response.0Wait but the angle given says 33 degrees?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1352584030549:dw

butterflyprincess
 3 years ago
Best ResponseYou've already chosen the best response.0but how would you get the component form..... like what exactly do i solve for? w?

butterflyprincess
 3 years ago
Best ResponseYou've already chosen the best response.0mhm, okay but how do you know what you have to minus 33 with 15?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.1we want the angle between the ramp and the force the ramp is at an angle of 15 deg to the horizontal the force is at an angle of 33 deg to the horizontal therefore the angle between the force and the ramp is 3315deg

butterflyprincess
 3 years ago
Best ResponseYou've already chosen the best response.0Oh okay cool, so how can you set it up to get W?cos 18 = 2.5lbs/w..?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.1start with cos(theta)=F/W where F is the component parallel to the plane we set theta=18 and F=2.5 now yuo can solve for W

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.1cuz it's a right triangle...dw:1352584629296:dw

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.1cos(theta)=adj/hyp=F/W

butterflyprincess
 3 years ago
Best ResponseYou've already chosen the best response.0ohh Okay so W=2.63/

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.1I dunno, let me find a calculator...

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.1yep, I get the same :)

butterflyprincess
 3 years ago
Best ResponseYou've already chosen the best response.0oh okay but the answer says in the book <2.20,1.43> so how can i get there?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.1those must be the *components* of W, so it is W*cos(phi) W*sin(phi) where phi is the angle that W makes with the horizontal

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1352585011969:dwhere my exaggerated drawing doesn't work so well :P but Wx and Wy are the x and y components respectively

butterflyprincess
 3 years ago
Best ResponseYou've already chosen the best response.0what so youd get like (2.62 cos (18) , 2.62 sin (18)?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.118 is not the angle that W makes with the horizontal...

butterflyprincess
 3 years ago
Best ResponseYou've already chosen the best response.0wait really then what would it be?O:
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