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butterflyprincess Group Title

QUICK QUESTION!!** PIC INCLUDED* Suppose that a box is being towed up an inclined plane as shown in the figure. Find the force w needed to make the component of the force parallel to the inclined plane equal to 2.5 lb. Give answer in component form.

  • one year ago
  • one year ago

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  1. redshift Group Title
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    We will need that figure to know exactly what is being asked.

    • one year ago
  2. butterflyprincess Group Title
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    Here is a picture!

    • one year ago
  3. butterflyprincess Group Title
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    Does anyone know how to solve it D=

    • one year ago
  4. TuringTest Group Title
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    |dw:1352583686628:dw|

    • one year ago
  5. TuringTest Group Title
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    |dw:1352583791078:dw|

    • one year ago
  6. TuringTest Group Title
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    the component parallel to the plane is the magnitude of the force W time the cosine of the angle between the force and the plane, which is 30-15=15degrees

    • one year ago
  7. butterflyprincess Group Title
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    Wait but the angle given says 33 degrees?

    • one year ago
  8. TuringTest Group Title
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    sorry, good eye

    • one year ago
  9. TuringTest Group Title
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    |dw:1352584030549:dw|

    • one year ago
  10. butterflyprincess Group Title
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    ohokkk

    • one year ago
  11. butterflyprincess Group Title
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    but how would you get the component form..... like what exactly do i solve for? w?

    • one year ago
  12. TuringTest Group Title
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    yes

    • one year ago
  13. butterflyprincess Group Title
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    mhm, okay but how do you know what you have to minus 33 with 15?

    • one year ago
  14. TuringTest Group Title
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    we want the angle between the ramp and the force the ramp is at an angle of 15 deg to the horizontal the force is at an angle of 33 deg to the horizontal therefore the angle between the force and the ramp is 33-15deg

    • one year ago
  15. butterflyprincess Group Title
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    Oh okay cool, so how can you set it up to get W?cos 18 = 2.5lbs/w..?

    • one year ago
  16. TuringTest Group Title
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    start with cos(theta)=F/W where F is the component parallel to the plane we set theta=18 and F=2.5 now yuo can solve for W

    • one year ago
  17. TuringTest Group Title
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    cuz it's a right triangle...|dw:1352584629296:dw|

    • one year ago
  18. TuringTest Group Title
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    cos(theta)=adj/hyp=F/W

    • one year ago
  19. butterflyprincess Group Title
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    ohh Okay so W=2.63/

    • one year ago
  20. TuringTest Group Title
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    I dunno, let me find a calculator...

    • one year ago
  21. butterflyprincess Group Title
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    lol ok

    • one year ago
  22. TuringTest Group Title
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    yep, I get the same :)

    • one year ago
  23. butterflyprincess Group Title
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    oh okay but the answer says in the book <2.20,1.43> so how can i get there?

    • one year ago
  24. TuringTest Group Title
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    those must be the *components* of W, so it is W*cos(phi) W*sin(phi) where phi is the angle that W makes with the horizontal

    • one year ago
  25. TuringTest Group Title
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    |dw:1352585011969:dw|here my exaggerated drawing doesn't work so well :P but Wx and Wy are the x and y components respectively

    • one year ago
  26. butterflyprincess Group Title
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    what so youd get like (2.62 cos (18) , 2.62 sin (18)?

    • one year ago
  27. butterflyprincess Group Title
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    D:

    • one year ago
  28. TuringTest Group Title
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    18 is not the angle that W makes with the horizontal...

    • one year ago
  29. butterflyprincess Group Title
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    wait really then what would it be?O:

    • one year ago
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