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We will need that figure to know exactly what is being asked.

Here is a picture!

Does anyone know how to solve it D=

|dw:1352583686628:dw|

|dw:1352583791078:dw|

Wait but the angle given says 33 degrees?

sorry, good eye

|dw:1352584030549:dw|

ohokkk

but how would you get the component form..... like what exactly do i solve for? w?

yes

mhm, okay but how do you know what you have to minus 33 with 15?

Oh okay cool, so how can you set it up to get W?cos 18 = 2.5lbs/w..?

cuz it's a right triangle...|dw:1352584629296:dw|

cos(theta)=adj/hyp=F/W

ohh Okay so W=2.63/

I dunno, let me find a calculator...

lol ok

yep, I get the same :)

oh okay but the answer says in the book <2.20,1.43>
so how can i get there?

what so youd get like (2.62 cos (18) , 2.62 sin (18)?

D:

18 is not the angle that W makes with the horizontal...

wait really then what would it be?O: